Question:
The general solution of the differential equation xy' = y
Last updated: 7/24/2022
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The general solution of the differential equation xy' = y + √x² + y² for x > 0 is given by (with an arbitrary positive constant k) (A) ky² = x + √x² + y² (B) kx² = x + √x² + y² (C) kx²=y+√x² + y² (D) ky² = y + √x² + y²