Question:
Use Descartes' rule of signs to determine the total number
Last updated: 7/13/2022
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Use Descartes' rule of signs to determine the total number of real zeros and the number of positive and negative real zeros. (Hint: First factor out x to its lowest power.) f(x) = 5x11+ 2x9 + 9x7 - 9x6 Select one: a. 7 real zeros; f(x) has 1 positive real zero, no negative real zeros and the number 0 is a zero of multiplicity 6. b. 2 real zeros; f(x) has 1 positive real zero, no negative real zeros and the number 0 is a zero of multiplicity 1. c. 11 real zeros; f(x) has 1 positive real zero, 4 negative real zeros and the number 0 is a zero of multiplicity 6. d. 6 real zeros; f(x) has 1 positive real zero, no negative real zeros and the number 0 is a zero of multiplicity 5.