Math - Others Questions

Arrange the values according to magnitude Greatest Least

A work sampling study is to be conducted on rush hour traffic 4 00 p m to 6 59 p m five days per week The study will encompass 40 days Determine the day hour and minute for 10 observations using the following procedure and table 1 2 1 6912 7264 2 3491 1192 3 4715 2486 3264 1918 4 5 8510 4237 2044 3957 1632 1546 1950 1844 7209 0938 2376 6 3950 1328 7343 6083 7 7871 7752 0521 8511 8 2716 9 2935 10 8533 11 8818 9912 3761 4028 9207 9585 1039 2159 2438 2768 4666 9530 3352 2951 0131 4359 3095 4421 3018 1396 7354 0249 8259 9957 0538 1640 12 3 4 2811 8921 0575 7547 2093 2776 2664 3856 1123 0120 2128 3956 7728 Observation 1 a Read two digit numbers going down the first two digits of column 1 e g 69 34 47 and then down the second two digits of that column e g 12 9115 for days b For hours read one digit numbers going from left to right across row 3 and then across row 4 Read only 4s 5s and 6s c For minutes read two digit numbers going down column 1 first using the last two digits e g 12 91 15 and after exhausting those numbers repeat using the first two digits of that column e g 69 34 47 16 2 3 4 Arrange your times chronologically by day then hour and then minute Enter hours as a single digit 4 5 or 6 without a leading zero Day 5 4627 Time 6 8387 4617 16 33 38 15

recent publication The data by state are shown in the table Average Length of Stay stem 5 7 8 9 State Alabama 456 Alaska 37 Arizona Arkansas California Colorado Connecticut Delaware D C Florida Georgia Hawaii Idaho Illinois Indiana 6 11356677889999 Iowa Kansas No of Hospitals leaf 0111111222223334445579 120 15 60 87 441 72 34 9 12 226 163 20 42 210 114 122 7 1 X 5 8 7 1 6 1 5 4 Maine 7 4 State 7 1 Kentucky 6 9 Michigan 7 1 Louisiana 7 5 Minnesota 6 7 Mississippi 7 2 Maryland Massachusetts 7 9 Missouri Montana 9 3 Nevada Nebraska New Hampshire 7 2 New Jersey 6 5 New Mexico 8 5 New York N Carolina No of Hospitals 106 135 39 50 102 176 147 101 132 54 91 22 26 95 36 232 118 Average Length of Stay 6 8 6 6 7 3 7 2 8 6 6 9 Oregon 7 3 6 9 Pennsylvania 7 3 State N Dakota 6 3 Ohio 7 1 Oklahoma 5 4 Rhode Island S Carolina 10 1 Texas S Dakota 9 7 Utah Tennessee Vermont Virginia 7 5 Washington W Virginia 10 0 Wisconsin No of Hospitals 48 194 114 65 237 13 69 51 121 420 43 16 97 91 60 128 26 Average Length of Stay 11 0 6 7 6 6 5 4 7 4 6 8 7 0 132 7 2 Wyoming Make a stem and leaf display of the data for the average length of stay in days Enter numbers from smallest to largest separated by spaces Enter NONE for stems with no values 10 2 6 9 6 1 5 3 7 7 7 1 5 7 7 2 7 4 8 4

Recently people have a tendency to check a movie s review online before deciding whether watching the movie is worth the time and money One of the most prominent web sites for movie reviews is Rotten Tomatoes which is well known for scoring movies by collecting information from several film critics A sample of 18 random movies from 2020 gave the following ratings on the web site a Make a stem and leaf display for these data Enter numbers from smallest to largest separated by spaces Enter NONE for stems with no values stem 2 3 4 5 6 7 00 8 66 94 92 97 61 54 79 70 59 59 71 70 76 73 89 81 42 29 9 leaf b What shape does the distribution appear to take on O uniform skewed left skewed right mound shaped symmetric

How long did real cowboys live One answer may be found in the book The Last Cowboys by Connie Brooks University of New Mexico Press This delightful book presents a thoughtful sociological study of cowboys in West Texas and Southeastern New Mexico around the year 1890 A sample of 32 cowboys gave the following years of longevity stem 4 a Make a stem and leaf display for these data Enter numbers from smallest to largest separated by spaces Enter NONE for stems with no values 5 6 7 8 72 60 69 74 71 72 86 83 89 58 76 9 77 85 94 57 leaf 46 b Consider the following quote from Baron von Richthofen in his Cattle Raising on the Plains of North America Cowboys are to be found among the sons of the best families The truth is probably that most were not a drunken gambling lot quick to draw and fire their pistols Does the data distribution of longevity lend credence to this quote No these cowboys did not live long lives as evidenced by the high frequency of leaves for stems 4 and 5 i e 40 year old and 50 year old Sort of these cowboys lived somewhat long lives as evidenced by the high frequency of leaves for stems 5 and 6 1 e 50 year old and 60 year old Yes these cowboys certainly lived long lives as evidenced by the high frequency of leaves for stems 7 8 and 9 i e

Design a schedule of work sampling observations in which eight observations are made during one eight hour day Using the following table read the last digit going down column 1 for hours e g 21520 and read across row 4 from left to right in sets of two for minutes e g 16 32 15 46 Arrange the times chronologically Note It is only possible to sample observations between 00 00 and 07 59 Therefore discard any sampled hour or minute values that do not conform to this time range Leave no cells blank be certain to enter 0 wherever required 1 6912 2 3491 3 4715 2486 2776 4 1632 5 8510 7209 0938 2376 0120 6 3950 1328 7871 7343 6083 2108 7752 0521 8511 3956 8 2716 1396 7354 0249 7728 9 2935 8259 9912 3761 4028 10 8533 9957 9585 1039 2159 11 0508 1640 2768 4666 9530 12 2951 0131 4359 3095 4421 HH2 7 2 3 7264 2801 8901 4627 8387 1192 0575 7547 2093 4617 2664 3856 1546 1950 1844 1123 0064 1908 4237 Chronological order Time Observation 1 2 3 4 5 6 7 0 0 1 1 225 2044 3957 8818 9207 2438 3352 3018

With the age of cellphones adults have relied on the use of text messages as a fast and efficient way to communicate This has le many researchers to believe that more adults spend their time sending text messages rather than talking on their phone A sampl of 22 random adults was surveyed on the number of text messages they believe they send a day This gave the following counts 124 95 77 64 84 96 54 147 92 85 113 36 100 99 83 75 69 53 94 103 47 134 a Make a stem and leaf display for this data Enter numbers from smallest to largest separated by spaces Enter NONE for stems with no values stem 3 4 5 6 7 8 00 9 10 11 12 13 14 leaf b Comment about the general shape of the distribution skewed right uniform O fairly symmetric

How many observations should a time study analyst plan for in an operation that has a standard deviation of 3 1 minutes per piece The goal is to estimate the mean time per piece to within 1 3 minutes with a confidence of 95 5 percent Do not round intermediate calculations Round up your final answer to the next whole number Numbe

In an initial survey designed to estimate the percentage of time air express cargo loaders are idle an analyst found that loaders were idle in 4 of the 50 observations a What is the estimated percentage of idle time Round your answer to 2 decimal places Estimated percentage of idle time b Based on the initial results approximately how many observations would you require to estimate the actual percentage of idle time to within 3 percent with a confidence of 99 percent Round your z value to 2 decimal places Do not round any other intermediate calculations Round UP your final answer to the next whole number

Wetlands offer a diversity of benefits They provide a habitat for wildlife spawning grounds for U S commercial fish and renewable timber resources In the last 200 years the United States has lost more than half its wetlands Environmental Almanac gives the percentage of wetlands lost in each state in the last 200 years For 30 of the lower 48 states the percentage loss of wetlands per state is as follows 26 49 54 50 38 46 46 72 67 56 24 81 50 39 35 35 50 35 91 48 56 86 52 36 Make a stem and leaf display of these data How are the percentages distributed Is the distribution skewed Are there any gaps Step 1 We are given the following data set and we are to make a stem and leaf display of this data 60 89 46 31 28 26 49 54 50 38 46 46 72 67 56 24 81 50 39 35 35 36 8 60 89 46 31 28 50 35 91 48 56 86 52 Recall that a stem and leaf display is a method of exploratory data analysis that is used to rank order and arrange data into groups The digits of each data value will be divided into two parts The leftmost part is called the stem and the rightmost part is called the leaf The largest number in this data set is a two digit number so we need to first write all the numbers in the data set as two digit numbers by adding leading zeros as needed 26 49 54 50 38 46 46 72 67 56 24 81 50 39 35 35 50 35 91 48 56 86 52 36 08 60 89 46 31 28 49 50 50 50 52 54 56 56 Since all the numbers for the data are now two digit numbers the stem will be the number in the tens place and the leaf will be the number in the ones 0 place Now organize the numbers in the data set from smallest to largest value 08 24 26 28 31 35 35 36 38 39 46 46 60 67 72 81 46 48 89 91

Suppose a research firm included data by state on the number of community hospitals and the average patient stay in days in a recent publication The data by state are shown in the table stem 5 6 7 8 9 10 State 11 Alabama Alaska Arizona Arkansas California Colorado Connecticut Delaware D C Florida Georgia Hawaii Idaho Illinois Indiana Iowa Kansas No of Hospitals leaf 120 15 60 87 441 72 34 9 12 226 163 20 42 210 114 122 132 Average Length of Stay 7 1 X 5 4 5 8 Louisiana 7 1 7 5 6 7 6 1 Massachusetts 7 4 6 9 Michigan 7 1 7 1 State Kentucky 7 2 7 2 Maine Maryland Minnesota Comment about the general shape of the distribution The dint Mississippi Missouri 9 3 Nevada Montanal Nebraska New Hampshire New Jersey 6 5 New Mexico 8 5 New York 7 9 N Carolina No of Hospitals 106 135 39 50 102 176 147 101 132 54 91 22 26 95 36 232 118 Average Length of Stay 6 8 N Dakota 6 6 Ohio 7 3 6 9 6 9 7 2 8 6 7 3 9 7 6 3 State 7 1 7 5 5 4 Oklahoma 7 3 Tennessee 10 0 Oregon 10 1 Texas Pennsylvania Rhode Island S Carolina S Dakota Utah Vermont Virginia Washington W Virginia Wisconsin 7 2 Wyoming No of Hospitals 48 194 114 65 237 13 69 51 121 420 43 16 97 91 60 N 128 26 Average Length of Stay 11 0 6 7 6 6 5 4 7 4 6 8 7 0 Make a stem and leaf display of the data for the average length of stay in days Enter numbers from smallest to largest separated by spaces Enter NONE for stems with no values 10 2 6 9 6 1 5 3 7 7 7 1 5 7 7 2 7 4 8 4

Recall that an ogive is a graph that displays cumulative frequencies where the cumulative frequency for a class is the sum of the frequencies for that class and all the previous classes We will use the class boundaries and the corresponding cumulative frequencies to create an ogive Class Limits Class Boundaries Cumulative Frequency 28 38 39 49 50 60 61 71 72 82 27 5 38 5 38 5 49 5 49 5 60 5 60 5 71 5 71 5 82 5 For the ogive we use the cumulative frequency on the vertical 5 30 47 49 50 axis There are five classes in the table so

c Draw a histogram Use the class boundaries and the corresponding frequencies to create a histogram Class Limits Class Boundaries Frequency 5 28 38 39 49 50 60 61 71 72 82 27 5 38 5 38 5 49 5 49 5 60 5 60 5 71 5 71 5 82 5 25 17 1 Recall that the class frequency determines the height of each bar So to construct the histogram include a range g than the highest frequency value to accommodate the frequency on the vertical axis There are five classes in the table so there are X vertical bars The values for each vertical bar will b made clear with the lower class boundary to the left of its respective bar and the upper class boundary to the right

Now determine the frequencies The class frequency is the total number of data values in that class Recall that each dat value should fall into exactly one class Now examine the data set and determine how many data values fall into each class Note that with such a large number of values you may find it helpful to order the data first 28 38 Complete the table 39 49 50 60 28 33 33 35 38 39 40 40 41 41 41 42 43 43 44 61 71 45 46 46 47 Class Limits Class Boundaries 72 82 51 51 51 52 52 27 5 38 5 38 5 49 5 49 5 60 5 47 47 60 5 71 5 71 5 82 5 3 47 47 47 48 48 48 49 50 51 51 51 54 55 55 55 56 57 Frequency x X X x x 60 44 45 65 69 81

We will now determine the midpoint of each class Recall that the midpoint is the average of each class Find the average by dividing the sum of the class boundaries by 2 Complete the table Class Boundaries 27 5 38 5 38 5 49 5 49 5 60 5 60 5 71 5 71 582 5 28 38 39 49 Complete the table 50 60 45 61 71 27 5 38 5 2 38 5 49 5 2 55 66 51 51 51 77 Step 6 Now determine the frequencies The class frequency is the total number of data values in that class Recall that each data value should fall into exactly one class Now examine the data set and determine how many data values fall into each class Note that with such a large number of values you may find it helpful to order the data first Midpoint Class Limits Class Boundaries 44 28 33 33 35 38 39 40 40 27 5 38 5 33 46 46 47 47 47 47 38 5 49 5 55 49 5 60 5 66 60 5 71 5 77 52 52 53 54 44 47 55 Frequency x x 41 41 41 42 43 43 44 44 45 48 49 50 51 51 51 57 60 65 69 47 48 48 55 55 56 81

Evaluate each expression using the graphs of y f x and y g x shown below a f g 8 b g f 3 c f g 4 f g f g 2 d g f 7 e f f 3 a f g 8 Type a whole number C 10 9 8 7 YA 6 5 3 2 0 y f x A y g x 1 2 3 4 5 6 7 8 9

A buoy floating in the ocean is bobbing in simple harmonic motion with period 8 seconds and amplitude 4 ft Its displacement from sea level at time t 0 seconds is 0 ft and initially it moves downward Note that downward is the negative direction Give the equation modeling the displacement d as a function of time t d 0 T sin cos

Calculate the length of the line segment defined by each pair of endpoin a A 6 2 and B 4 3 b J 2 1 8 3 and K 4 5 4 7

2 Determine the perimeter of the triangle 6 A 5 2 YA 61 A 2 20 ON C 1 7 24 2 6 B 4 1 Ax

Chan s new balance is 567 89 He made a payment of 123 45 He made a purchase of 89 00 The finance charge was 2 34 What was the previous balance

While your instructor was lecturing what happened outside the window house A kid fell off a bike A small fender bender between two cars Amazon prime delivery interrupted the lecture with a package A bird landed on the window pane

With new travel technologies the world seems to be getting smaller True False

Jake can mulch a garden in 30 minutes Together Jake and Ross can mulch the same garden in 16 minutes How much time t in minutes will it take Ross to mulch the garden when working alone

Certain kinds of tumors tend to recur Suppose the following data represent the lengths of time in months for a tumor to recur after chemotherapy 1 13 20 19 18 1 22 21 55 47 26 50 49 1 25 44 37 18 For this problem use five classes a Find the class width 12 38 6 10 37 37 39 USE SALT Class Limits 12 24 36 39 b Make a frequency table showing class limits class boundaries midpoints frequencies relative frequencies and cumulative frequencies Round your relative frequencies to four decimal places 48 2 0 5 12 17 24 1 36 15 Class Boundaries Midpoint Frequency 42 11 51 42 26 18 40 28 19 12 1 46 24 1 53 59 47 51 36 1 48 6 5 59 38 18 30 11 30 1 42 1 X X X X Relative Frequency X Cumulative Frequency x

a Find the class width Recall that the class width is computed by finding the difference of the largest data value and the smallest data value and dividing that difference by the desired number of classes Here we are asked to use five classes Therefore we have the following class width Now examine the data set and determine the largest and smallest data values Percent Male Students Enrolled in Coed Universities and Colleges 33 41 51 49 42 51 55 45 47 28 41 81 47 52 38 47 47 51 41 50 56 52 45 44 40 33 51 43 44 60 40 57 47 69 V The largest data value is 81 largest data value smallest data value desired number of classes 48 55 51 48 47 48 51 46 55 35 54 65 39 43 53 46 Step 3 largest data value smallest data value 7 5 X Step 2 Substitute the largest data value 81 and the smallest data value 28 into the formula for finding the class width for five classes and simplify the result largest data value class width 10 6 81 28 First class Third class 5 Second class The result is not an integer but it is illogical to talk about a fraction of a student Here to ensure the classes cover all the data we should round this value up to the next whole number Doing this allows us to state that the class width is 11 11 Fourth class b Make a frequency table showing class limits class boundaries midpoints frequencies relative frequencies and cumulative frequencies 5 Recall that a frequency table partitions data into classes or intervals of equal width The process of creating a frequency table has many steps First we will create the five distinct classes Determine all lower and upper class limits knowing that the smallest value is 28 the largest value is 81 and the class width is 11 39 ng 81 and the smallest data value is 28 smallest data value 28 10 6 50 61 Lower class limit Upper class limit 28 38 60

A construction crew is lengthening a road Let L be the total length of the road in miles Let D be the number of days the crew has worked Sup that L 4D 300 gives L as a function of D The crew can work for at most 80 days Identify the correct description of the values in both the domain and range of the function Then for each choose the most appropriate set of valu Domain Range Description of Values Onumber of days the crew has worked Olength of the road in miles Onumber of days the crew has worked Olength of the road in miles Set of Values Choose one Choose one

The following data represent baseball batting averages for a random sample of National League players near the end of the baseball season 195 126 0 195 0 257 0 191 0 290 0 159 0 294 216 0 126 0 106 0 259 0 308 0 308 0 275 0 216 0 251 0 245 0 259 0 264 0 183 a Multiply each data value by 1 000 to clear the decimals Keep data values in the same order they appear in the table above 257 106 X 251 Class Limits 191 X 259 245 290 308 259 0 260 0 249 0 182 0 286 0 316 0 253 0 114 0 199 159 308 264 100 294 275 183 Class Boundaries Midpoint Frequency 260 286 114 b Use the standard procedures of this section to make a frequency table with your whole number data Use five classes 249 316 199 182 253

The Sugar Sweet Company delivers sugar to its customers Let C be the total cost to transport the sugar in dollars Let S be the amount of sugar transported in tons The company can transport up to 20 tons of sugar Suppose that C 130S 1500 gives C as a function of S Identify the correct description of the values in both the domain and range of the function Then for each choose the most appropriate set of values 5 Domain Range Description of Values O amount of sugar transported in tons O cost to transport sugar in dollars O amount of sugar transported in tons O cost to transport sugar in dollars Set of Values Choose one Choose one

sample of 50 such institutions give the following data Percent Male Students Enrolled in Coed Universities and Colleges 33 41 51 49 42 51 55 45 47 28 41 81 47 52 38 47 47 41 50 56 52 45 44 40 33 51 43 44 60 40 57 47 69 51 48 55 51 48 For this problem use five classes a Find the class width c Draw a histogram Step 1 b Make a frequency table showing class limits class boundaries midpoints frequencies relative frequencies and cumulative frequencies d Draw a relative frequency histogram e Categorize the basic distribution shape f Draw an ogive a Find the class width 47 48 51 46 55 35 54 Recall that the class width is computed by finding the difference of the largest data value and the smallest data value and dividing that difference by the desired number of classes Here we are asked to use five classes Therefore we have the following class width largest data value smallest data value desired number of classes largest data value smallest data value 51 41 50 Now examine the data set and determine the largest and smallest data values Percent Male Students Enrolled in Coed Universities and Colleges 33 41 51 49 42 51 55 45 47 28 41 81 47 52 38 47 48 55 51 The largest data value is 56 52 45 48 44 40 5 65 39 43 53 46 33 51 43 47 48 51 46 55 35 54 44 60 40 57 47 69 65 39 43 53 46 47 an and the smallest data value is e is

Given the following information set up the problem in a transportation table and solve for the minimum cost plan PERIOD 2 700 Demand Capacity Regular Overtime Subcontract Beginning inventory Costs Regular time Overtime Subcontract Inventory carrying cost Back order cost 550 500 50 120 100 60 per unit 80 per unit 90 per unit 500 50 120 1 per unit per month 3 per unit per month 3 750 440 50 100 Suppose the inventory carrying cost has just increased and is now 2 per unit per period Compute the total cost for the original transportation model with 1 inventory carrying cost and the new total cost at 2 carrying cost What is the additional cost for the optimal plan

Determine the optimum preventive maintenance frequency for each of the pieces of equipment if breakdown time is normally distributed Round Probability Ratio to 4 decimal places and all other answers to 2 decimal places Negative values should be indicated by a minus sign Use Table Equipment A201 B400 C850 Equipment A201 B400 C850 Equipment Average Time days between Breakdowns A201 0400 19 31 36 Click here for the Excel Data File Preventive Maintenance Cost 240 140 490 Probability Ratio Standard Deviation 2 3 6 Breakdown Cost 2 140 3 440 4 600 Interval days

A manager must make a decision on shipping There are two shippers A and B Both offer a two day rate A for 530 and B for 521 In addition A offers a three day rate of 466 and a nine day rate of 417 and B offers a four day rate of 459 and a seven day rate of 432 Annual holding costs are 37 percent of unit price Three hundred and twenty boxes are to be shipped and each box has a price of 154 Which shipping alternative would you recommend Round your intermediate calculations to 3 decimal places and final answers to 2 decimal places Option 2 days 3 days 9 days A Cost ship two day using A O ship three day using A O ship seven day using B O ship four day using B Oship two day using B Option 2 days 4 days 7 days B Cost

hour for 52 dogsled teams are shown below O O O 240 240 Draw or use technology to make a dotplot for the data above regarding the finish time number of hours for the Iditarod Dog Sled Race 240 260 270 235 243 278 295 285 298 287 287 248 257 337 360 342 332 262 267 286 297 312 312 308 240 278 282 305 306 287 289 289 290 296 298 331 329 329 308 327 306 327 327 286 290 294 297 307 314 311 317 317 321 PROCEDURE How to Make a Dotplot Display the data along a horizontal axis Then plot each data value with a dot or point above the corresponding value on the horizontal axis For repeated data values stack the dots Frequency 30 25 USE SALT 20 15 10 5 260 260 260 260 280 280 Consider the following histogram of the data 300 Finish Times 280 00000 280 300 Finish Times 300 Finish Times 000000 GD 300 Finish Times 0 234 5 260 5 286 5 312 5 338 5 364 5 Finish Times 320 n 308 300 320 320 300 304 320 Compare the dotplot to a histogram of the data above Select all that apply The dotplot and histogram both show a greater density from 280 to 340 O Histograms show the frequency of individual data values 340 340 340 340 360 360 360 360 G

Certain kinds of tumors tend to recur Suppose the following data represent the lengths of time in months for a tumor to recur after chemotherapy 20 19 18 1 22 21 55 47 44 38 6 10 39 17 15 46 18 37 37 39 42 42 11 51 42 26 18 40 28 19 USE SALT For this problem use five classes a Find the class width 1 1 26 50 49 1 59 38 53 59 47 51 30 11 b Make a frequency table showing class limits class boundaries midpoints frequencies relative frequencies and cumulative frequencies Round your relative frequencies to four decimal places Class Limits Class Boundaries Midpoint Frequency Relative Frequency Cumulative Frequency 0 0 000 000 000 000

What is the difference between a class boundary and a class limit Select all that apply Class limits are not possible data values Class boundaries are possible data values 0000 Class limits are values halfway between the upper class boundary of one class and the lower class boundary of the nex Class boundaries specify the span of data values that fall within a class Class limits specify the span of data values that fall within a class Class boundaries are values halfway between the upper class limit of one class and the lower class limit of the next Class limits are possible data values Class boundaries are not possible data values

manager at Strateline Manufacturing must choose between two shipping alternatives two day freight and five day freight Using e day freight would cost 180 less than using two day freight The primary consideration is holding cost which is 8 per unit a year 300 items are to be shipped hich alternative would you recommend Do not round your intermediate calculations O Five day freight OTwo day freight

Determine which shipping alternative would be most economical to ship 135 boxes of parts when each box has a price of 200 and holding costs are 30 percent of price given this shipping information overnight 320 two day 260 six day 180 Round your intermediate calculations to 2 decimal places O Overnight O Six day O Two day

The frequency of breakdown of a machine that issues lottery tickets is given in the following table Repairs cost an average of 233 A service firm is willing to provide preventive maintenance under either of two options 1 is 503 and covers all necessary repairs and 2 is 369 and covers any repairs after the first one Do not round intermediate calculations Round your final answer to the nearest whole number Number of breakdowns month Frequency of occurrence Click here for the Excel Data File Pay for all repairs Service option 1 Service option 2 0 1 2 3 4 10 30 25 15 20 Which option would have the lowest expected cost pay for all repairs service option 1 or service option 2 O Pay for all repairs O Service option 1

The probability that equipment used in a hospital lab will need recalibration is given in the following table A service firm is willing to perform maintenance and do any necessary calibrations for a fee of 500 per month Recalibration costs 425 per time Round the answer of Expected cost of recalibration to nearest whole number Number of Recalibrations Probability of Occurrence Click here for the Excel Data File Expected cost of recalibration Service contract cost 0 15 1 30 2 30 3 15 4 10 Which approach would be most cost effective recalibration as needed or the service contract O Service contract O Recalibration

92 Convert the fraction to a whole number percentage 248

Convert the decimal number 0 008 to a whole number percentage

Convert the decimal number 0 007 to a whole number percentage

Convert the decimal number 0 473 to a whole number percentage

For questions 7 10 solve the problem by following the procedure for solving an optimization problem Show all your steps Include a concluding statement that summarizes your answer and includes the correct units 7 An apple orchard now has 80 trees per hectare and the average yield is 400 apples per tree For each additional tree planted per hectare the average yield per tree is reduced by approximately four apples How many trees per hectare will give the largest crop of apples 8 Time to Travel advertises a package plan for an Arizona vacation The fare for the flight is 400 person plus 8 person for each unsold seat on the plane The plane holds 120 passengers and the flight will be cancelled if there are fewer than 25 passengers What number of passengers will maximize revenue

The Pie Emporium cuts its Boston cream pies into 8 slices If diners at a table order 5 slices of Boston cream pie for dessert what percentage of a pie did they consume Round the answer to the nearest whole percentage Simplify your answer completely

Convert the decimal number 0 946 to a whole number percentage

Convert the fraction 8 to a whole number percentage 54

Convert the fraction X 415 1 245 to a whole number percentage

Convert the decimal number 0 958 to a whole number percentage X

Prepare a master production schedule for industrial pumps in the manner of the following table Use the MPS rule to schedule production when the projected on hand inventory would be less than 10 without production Suppose that there are currently 64 pumps in inventory and a production lot size of 70 pumps is used Leave no cells blank be certain to enter 0 wherever required Forecast Customer orders committed Projected on hand inventory MPS ATP 30 33 2 June 30 20 3 30 10 4 30 4 5 40 2 6 July 40 7 40 8 40