Soru:
8. P(x) = x2 + 2x+ 1 = P(x - 1) = ? %3D A) x2 B) x2 – 2x C) x² + 2x D) x2 + 2x + 1 E) x2 – 2x + 1
![8. P(x) = x2 + 2x+ 1
= P(x - 1) = ?
%3D
A) x2
B) x2 – 2x
C) x² + 2x
D) x2 + 2x + 1
E) x2 – 2x + 1](https://media.kunduz.com/media/question/seo/raw/20200412102010462059-1575842_G99w1nL2N.jpg?h=512)
8. P(x) = x2 + 2x+ 1 = P(x - 1) = ? %3D A) x2 B) x2 – 2x C) x² + 2x D) x2 + 2x + 1 E) x2 – 2x + 1
Soru çözüm, yayın seti, birebir rehberlik, canlı dersler ve daha fazlası Kunduz’da. Şimdi al, netlerini artırmaya başla.
8. P(x) = x2 + 2x+ 1 = P(x - 1) = ? %3D A) x2 B) x2 – 2x C) x² + 2x D) x2 + 2x + 1 E) x2 – 2x + 1