Solution of triangles Questions and Answers

our Turn 1 12 unit Use the Triangle Inequality Theorem to fell with the given lengths Fynl
Geometry
Solution of triangles
our Turn 1 12 unit Use the Triangle Inequality Theorem to fell with the given lengths Fynl
Use the congruency statement to state corresponding congruent parts 16 AKIT AEAS 17 ALMO ANOM ZK ZS Z1 KT AS IK ZOMLE ZOMN ZN ON OL MO
Geometry
Solution of triangles
Use the congruency statement to state corresponding congruent parts 16 AKIT AEAS 17 ALMO ANOM ZK ZS Z1 KT AS IK ZOMLE ZOMN ZN ON OL MO
In 18 20 Find the indicated information 18 A 32 X y Z 19 X y 54 20 7x 10 X 13x 8 Find the length of each side 3x
Geometry
Solution of triangles
In 18 20 Find the indicated information 18 A 32 X y Z 19 X y 54 20 7x 10 X 13x 8 Find the length of each side 3x
In 6 7 6 1 m find the value of x and the measure of all the angles drawings are not to scale 7 6x 15 15x 3 m 130 2x 10
Geometry
Solution of triangles
In 6 7 6 1 m find the value of x and the measure of all the angles drawings are not to scale 7 6x 15 15x 3 m 130 2x 10
In 10 11 If possible write a congruency statement and state the theorem SSS use to prove the triangles congruent 10 R A U Congruence Statement Reason T 11 E Reason D Congruence Statement C
Geometry
Solution of triangles
In 10 11 If possible write a congruency statement and state the theorem SSS use to prove the triangles congruent 10 R A U Congruence Statement Reason T 11 E Reason D Congruence Statement C
13 Given 20 ZQ P is the midpoint of OQ Prove AMOP ANQP M O P N Statement Reason
Geometry
Solution of triangles
13 Given 20 ZQ P is the midpoint of OQ Prove AMOP ANQP M O P N Statement Reason
Solve for x 15 B A D 2x 4 18 8 C
Geometry
Solution of triangles
Solve for x 15 B A D 2x 4 18 8 C
Question 8 Watch Video 4 Triangle STU is formed by connecting the midpoints of the side of triangle PQR The lengths of the sides of triangle PQR are shown What is the length of SU Figures not necessarily drawn to scale T Show Examples
Geometry
Solution of triangles
Question 8 Watch Video 4 Triangle STU is formed by connecting the midpoints of the side of triangle PQR The lengths of the sides of triangle PQR are shown What is the length of SU Figures not necessarily drawn to scale T Show Examples
ACCVIV clity to record the Description Common Shares Contributed Surplus Retained Earnings Cash COMING SHIGES Earnings Per Share Revenue Debt to Equity Ratio Debit 5 040 000 545 000 7 015 000 Credit 12 600 000 Place only one T in each row below indicating the impact of the share reacquisition journal entry on the following financial statement metrics Positive Negative Not No Impact Determinable
Geometry
Solution of triangles
ACCVIV clity to record the Description Common Shares Contributed Surplus Retained Earnings Cash COMING SHIGES Earnings Per Share Revenue Debt to Equity Ratio Debit 5 040 000 545 000 7 015 000 Credit 12 600 000 Place only one T in each row below indicating the impact of the share reacquisition journal entry on the following financial statement metrics Positive Negative Not No Impact Determinable
ACCVIV clity to record the Description Common Shares Contributed Surplus Retained Earnings Cash COMING SHIGES Earnings Per Share Revenue Debt to Equity Ratio Debit 5 040 000 545 000 7 015 000 Credit 12 600 000 Place only one T in each row below indicating the impact of the share reacquisition journal entry on the following financial statement metrics Positive Negative Not No Impact Determinable
Geometry
Solution of triangles
ACCVIV clity to record the Description Common Shares Contributed Surplus Retained Earnings Cash COMING SHIGES Earnings Per Share Revenue Debt to Equity Ratio Debit 5 040 000 545 000 7 015 000 Credit 12 600 000 Place only one T in each row below indicating the impact of the share reacquisition journal entry on the following financial statement metrics Positive Negative Not No Impact Determinable
an application ASA Click here to watch the video To find the distance AB across a river a distance BC 371 meters is laid off on one side of the river It is found that B 113 11 and C 11 18 Find AB The distance AB across the river is Do not round until the final answer The square meters meters A B 113 11 371 m 11 18 le number as needed O
Geometry
Solution of triangles
an application ASA Click here to watch the video To find the distance AB across a river a distance BC 371 meters is laid off on one side of the river It is found that B 113 11 and C 11 18 Find AB The distance AB across the river is Do not round until the final answer The square meters meters A B 113 11 371 m 11 18 le number as needed O
Click here to watch the video Solve the triangle ABC if the triangle exists B 35 12 a 39 7 b 28 8 CAR Select the correct choice below and fill in the answer boxes within the choice OA There is only 1 possible solution for the triangle The measurements for the remaining angles A and C and side c are as follows mZA mZC The length of side c Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed Round to the nearest tenth as needed OB There are 2 possible solutions for the triangle The measurements for the solution with the longer mZA mZC Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed The measurements for the solution with the shorter mZA mZc Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed side care as follows The length of side c Round to the nearest tenth as needed side c are as follows The length of side c Round to the nearest tenth as needed
Geometry
Solution of triangles
Click here to watch the video Solve the triangle ABC if the triangle exists B 35 12 a 39 7 b 28 8 CAR Select the correct choice below and fill in the answer boxes within the choice OA There is only 1 possible solution for the triangle The measurements for the remaining angles A and C and side c are as follows mZA mZC The length of side c Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed Round to the nearest tenth as needed OB There are 2 possible solutions for the triangle The measurements for the solution with the longer mZA mZC Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed The measurements for the solution with the shorter mZA mZc Simplify your answer Round to the nearest degree as needed Round to the nearest minute as needed side care as follows The length of side c Round to the nearest tenth as needed side c are as follows The length of side c Round to the nearest tenth as needed
Two fire lookout towers at points A and B are 3 mi apart Find the distances from points A and B to a fire at point Cif LABC is 76 51 and BAC is 85 38 Round to the nearest tenth of a mile The distance AC is approximately mi and the distance BC is approximately mi
Geometry
Solution of triangles
Two fire lookout towers at points A and B are 3 mi apart Find the distances from points A and B to a fire at point Cif LABC is 76 51 and BAC is 85 38 Round to the nearest tenth of a mile The distance AC is approximately mi and the distance BC is approximately mi
IJKL is a parallelogram Select the true statements used to prove that opposite angles of a parallelogram are congruent Select two I L Show your work here 53959555 25553938 B 7 5 J K ZB Z8 because same side interior angles are congruent when a transversal crosses parallel lines AIJL AKLJ by the side angle side congruence criterion Za Zo because alternate interior angles are congruent when a transversal crosses parallel lines Za Zy because same side interior angles are congruent when a transversal crosses parallel lines
Geometry
Solution of triangles
IJKL is a parallelogram Select the true statements used to prove that opposite angles of a parallelogram are congruent Select two I L Show your work here 53959555 25553938 B 7 5 J K ZB Z8 because same side interior angles are congruent when a transversal crosses parallel lines AIJL AKLJ by the side angle side congruence criterion Za Zo because alternate interior angles are congruent when a transversal crosses parallel lines Za Zy because same side interior angles are congruent when a transversal crosses parallel lines
Click on the graph to view a larger graph For the given angles x and y in the triangle given in the graph sin x tan x 5 secx y 3 and cos y and cot y and csc y
Geometry
Solution of triangles
Click on the graph to view a larger graph For the given angles x and y in the triangle given in the graph sin x tan x 5 secx y 3 and cos y and cot y and csc y
10 cm Find the area 18 cm 17 cm 21 cm A cm A b h
Geometry
Solution of triangles
10 cm Find the area 18 cm 17 cm 21 cm A cm A b h
6 133 X y Z to Z 20
Geometry
Solution of triangles
6 133 X y Z to Z 20
3x 5 2x 8x 20
Geometry
Solution of triangles
3x 5 2x 8x 20
3y 18 9x 54 y 12
Geometry
Solution of triangles
3y 18 9x 54 y 12
9 X 2x 2X 6
Geometry
Solution of triangles
9 X 2x 2X 6
Step 1 Given Information Two official languages in Canada are English and French When a Canadian is chosen randomly and asked about their mother tongue the distribution of responses combining the majority of separate languages from the broad Asia Pacific region is as follows Probability of English is P E 0 63 Probability of French is P F Probability of Other languages from Asia Pacific region is P A p 0 06 Step 2 Probability Distribution In a probability distribution The probabilities must be non negative The sum of probabilities of all events should add up to 1 Using the second condition we can calculate the probability of Other languages from Asia Pacific region as P Other 1 P E P F P A p 10 91 0 09 0 22 Therefore the probability that should replace is 0 09 0 37 Step 3 Probability of not English The probability that a Canadian s mother tongue is not English can be calculated by using the complementary probability formula P notEnglish 1 P English 1 0 63 Therefore the probability that a Canadian s mother tongue is not English is 0 37 0 15 Step 4 Probability of Other languages The probability that a Canadian s mother tongue is a language other than English or French can be calculated by adding the probabilities of Other languages from Asia Pacific region and languages other than Official Languages i e P Asian Pacificor Other P Asian Pacific P Other 0 06 0 09 Therefore the probability that a Canadian s mother tongue is a language other than English or French is 0 15
Geometry
Solution of triangles
Step 1 Given Information Two official languages in Canada are English and French When a Canadian is chosen randomly and asked about their mother tongue the distribution of responses combining the majority of separate languages from the broad Asia Pacific region is as follows Probability of English is P E 0 63 Probability of French is P F Probability of Other languages from Asia Pacific region is P A p 0 06 Step 2 Probability Distribution In a probability distribution The probabilities must be non negative The sum of probabilities of all events should add up to 1 Using the second condition we can calculate the probability of Other languages from Asia Pacific region as P Other 1 P E P F P A p 10 91 0 09 0 22 Therefore the probability that should replace is 0 09 0 37 Step 3 Probability of not English The probability that a Canadian s mother tongue is not English can be calculated by using the complementary probability formula P notEnglish 1 P English 1 0 63 Therefore the probability that a Canadian s mother tongue is not English is 0 37 0 15 Step 4 Probability of Other languages The probability that a Canadian s mother tongue is a language other than English or French can be calculated by adding the probabilities of Other languages from Asia Pacific region and languages other than Official Languages i e P Asian Pacificor Other P Asian Pacific P Other 0 06 0 09 Therefore the probability that a Canadian s mother tongue is a language other than English or French is 0 15
7 Use the universal substitution to find the general solution of the equation 2 cos 3x sin 3x 2
Geometry
Solution of triangles
7 Use the universal substitution to find the general solution of the equation 2 cos 3x sin 3x 2
3 AZXY AZXC ZXZY ZCXZ ZC CZ XY XZ X
Geometry
Solution of triangles
3 AZXY AZXC ZXZY ZCXZ ZC CZ XY XZ X
1 ATUV AGFE ZT ZU ZV 2 AWVU AGHI ZHE ZW 21 3 AZXY AZXC ZXZY ZCXZ ZC 4 ADEF ADSR ZF ZS ZFDE and Mark corresponding congruent parts for the given congruent triangles U UV E EG UT VW VU E GI CZ XY XZ EF RD SD W R U G H
Geometry
Solution of triangles
1 ATUV AGFE ZT ZU ZV 2 AWVU AGHI ZHE ZW 21 3 AZXY AZXC ZXZY ZCXZ ZC 4 ADEF ADSR ZF ZS ZFDE and Mark corresponding congruent parts for the given congruent triangles U UV E EG UT VW VU E GI CZ XY XZ EF RD SD W R U G H
This application will assess the haze severity for Perak Malaysia Please enter the API Safety Level District 2 Genk Kuala Kangsar Ipoh Tronoh Taiping Calculate Average Level API Level Clear Level Exit Requirements 1 Name the frame labels textboxes and buttons accordingly 2 This application will assess the API Level for state of Perak It allows the user to enter the API Level for different districts in Perak Whenever the year leaves the API Laval taxthox of agah district laval for that specific API
Geometry
Solution of triangles
This application will assess the haze severity for Perak Malaysia Please enter the API Safety Level District 2 Genk Kuala Kangsar Ipoh Tronoh Taiping Calculate Average Level API Level Clear Level Exit Requirements 1 Name the frame labels textboxes and buttons accordingly 2 This application will assess the API Level for state of Perak It allows the user to enter the API Level for different districts in Perak Whenever the year leaves the API Laval taxthox of agah district laval for that specific API
57 Then use 3 Let s consider the unit circle for 0 900 180 270 and 360 Angles 0 90 180 270 4 360 1 X Now complete the chart for 0 900 1800 270 and 360 x y Sin YO 1 SOH CaH TOA Cos Consider the rt triangle in the unit circle y I zy Sin 0 Cos 0 Tan 0 Tan x y C 2x A
Geometry
Solution of triangles
57 Then use 3 Let s consider the unit circle for 0 900 180 270 and 360 Angles 0 90 180 270 4 360 1 X Now complete the chart for 0 900 1800 270 and 360 x y Sin YO 1 SOH CaH TOA Cos Consider the rt triangle in the unit circle y I zy Sin 0 Cos 0 Tan 0 Tan x y C 2x A
Put the following equation of a line into slope intercept form simplifying all fractions 3x 6y 36
Geometry
Solution of triangles
Put the following equation of a line into slope intercept form simplifying all fractions 3x 6y 36
Turn For each triangle order its angle measures from least to greatest
Geometry
Solution of triangles
Turn For each triangle order its angle measures from least to greatest
2 Find the measure of ZPRS 1260 R M 63 3x 8 5x 50 P x 2
Geometry
Solution of triangles
2 Find the measure of ZPRS 1260 R M 63 3x 8 5x 50 P x 2
5 Given BC CD ZB ZD Prove AB DE A D B C Statement Reason
Geometry
Solution of triangles
5 Given BC CD ZB ZD Prove AB DE A D B C Statement Reason
2 Given BC AD AC BD Prove ZBCD ZADC B D C A Statement Reason
Geometry
Solution of triangles
2 Given BC AD AC BD Prove ZBCD ZADC B D C A Statement Reason
6 Given GHK ZJHK ZGKH ZJKH Prove AGKH AJKH G K J Statement Reason
Geometry
Solution of triangles
6 Given GHK ZJHK ZGKH ZJKH Prove AGKH AJKH G K J Statement Reason
3 Solve the triangle below Round each answer to the nearest tenth 24 a C 36 16
Geometry
Solution of triangles
3 Solve the triangle below Round each answer to the nearest tenth 24 a C 36 16
2 y 113 b 10 c 32
Geometry
Solution of triangles
2 y 113 b 10 c 32
9 Given APQR with P 1 4 Q 3 0 and R 2 3 Prove APQR is NOT a right triangle 11 1 4 R 2 3 W Q 3 0 Mainita com
Geometry
Solution of triangles
9 Given APQR with P 1 4 Q 3 0 and R 2 3 Prove APQR is NOT a right triangle 11 1 4 R 2 3 W Q 3 0 Mainita com
Given ZRUY 90 and ZRST 90 Find YT A R 32 U 46 A Y
Geometry
Solution of triangles
Given ZRUY 90 and ZRST 90 Find YT A R 32 U 46 A Y
20 21 8 40 Q 43 75 For 19 21 find the values of x and y 19 Jo 77 96 R 1 y 35 2 xo st 4 S 3 64 7 5 6 mz1 mz2 mz3 m24 x x x m25 mz6 m27 m28 y y y
Geometry
Solution of triangles
20 21 8 40 Q 43 75 For 19 21 find the values of x and y 19 Jo 77 96 R 1 y 35 2 xo st 4 S 3 64 7 5 6 mz1 mz2 mz3 m24 x x x m25 mz6 m27 m28 y y y
Section 5 1 Worksheet 1 The measure of an exterior angle of a triangle is equal to the sum of the measures of the two interior angles For 2 5 classify the triangle by its sides and by its angle measures 2 X 3 M For 8 For 6 and 7 classify AABC by its sides Then determine whether it is a right triangle 6 A 2 3 B 6 3 C 2 7 7 A 3 3 B 6 9 C 6 3 Classify by sides Is it a right triangle N find m21 Then classify the triangle by its angles 78 319 4 J Classify by sides Is it a right triangle mz1 Classify by its angles 5 B A
Geometry
Solution of triangles
Section 5 1 Worksheet 1 The measure of an exterior angle of a triangle is equal to the sum of the measures of the two interior angles For 2 5 classify the triangle by its sides and by its angle measures 2 X 3 M For 8 For 6 and 7 classify AABC by its sides Then determine whether it is a right triangle 6 A 2 3 B 6 3 C 2 7 7 A 3 3 B 6 9 C 6 3 Classify by sides Is it a right triangle N find m21 Then classify the triangle by its angles 78 319 4 J Classify by sides Is it a right triangle mz1 Classify by its angles 5 B A
Solve the triangle a 8 103 in c 6 630 in B 78 63 What is the length of side b in Round to the nearest thousandth as needed What is the measure of angle A Round to the nearest hundredth as needed What is the measure of angle C O Round to the nearest hundredth as needed
Geometry
Solution of triangles
Solve the triangle a 8 103 in c 6 630 in B 78 63 What is the length of side b in Round to the nearest thousandth as needed What is the measure of angle A Round to the nearest hundredth as needed What is the measure of angle C O Round to the nearest hundredth as needed
Solve the triangle with the given parts a 25 3 m b 14 4 m c 14 3 m What is the degree measure of angle A 7 Round to the nearest tenth as needed
Geometry
Solution of triangles
Solve the triangle with the given parts a 25 3 m b 14 4 m c 14 3 m What is the degree measure of angle A 7 Round to the nearest tenth as needed
f x 2 cos x 2 cos x xx 3x 7x The solution set for f x 0 in the interval 0 2x is 4 2 24 Simplify your answer Type an exact answer using as needed Use integers or fractions for any numbers in the expression Use a comma to separate answers as needed Find the solution set for f x 0 in the specified interval Choose the correct answer below OA The solution set of f x 0 is 0 OB The solution set of f x 0 is x 3x 22 3x 7x 4 2 2 OC The solution set of f x 0 is 0
Geometry
Solution of triangles
f x 2 cos x 2 cos x xx 3x 7x The solution set for f x 0 in the interval 0 2x is 4 2 24 Simplify your answer Type an exact answer using as needed Use integers or fractions for any numbers in the expression Use a comma to separate answers as needed Find the solution set for f x 0 in the specified interval Choose the correct answer below OA The solution set of f x 0 is 0 OB The solution set of f x 0 is x 3x 22 3x 7x 4 2 2 OC The solution set of f x 0 is 0
Find the value of csc arccos Express numbers in exact form Use symbolic notation and fractions where needed Simplify your answer com
Geometry
Solution of triangles
Find the value of csc arccos Express numbers in exact form Use symbolic notation and fractions where needed Simplify your answer com
Listen Classify each angle pair as corresponding alternate interior alternate exterior or consecutive interior angles 1 2 3 4 910 1112 56 78 13 14 15 16 Corresponding angles Alternate interior angles Alternate exterio
Geometry
Solution of triangles
Listen Classify each angle pair as corresponding alternate interior alternate exterior or consecutive interior angles 1 2 3 4 910 1112 56 78 13 14 15 16 Corresponding angles Alternate interior angles Alternate exterio
2023 What is true about line segments AD and BD A B C E D B Line segments cannot be proven congruent Line segments are congruent due to the side side side congruence postulate Line segments are congruent due to the side side angle congruence postulate Line segments are congruent due to the side angle side congruence postulate Illuminate Education Inc
Geometry
Solution of triangles
2023 What is true about line segments AD and BD A B C E D B Line segments cannot be proven congruent Line segments are congruent due to the side side side congruence postulate Line segments are congruent due to the side side angle congruence postulate Line segments are congruent due to the side angle side congruence postulate Illuminate Education Inc
Question 11 Which postulate or theorem can be used to prove that AABC ADCB A B A B C SSS SAS ASA D
Geometry
Solution of triangles
Question 11 Which postulate or theorem can be used to prove that AABC ADCB A B A B C SSS SAS ASA D
D W X A Which additional information would be enough to prove that AXWY ADEC B C C D Y ZY ZD ZY ZE ZW LC ZW ZE
Geometry
Solution of triangles
D W X A Which additional information would be enough to prove that AXWY ADEC B C C D Y ZY ZD ZY ZE ZW LC ZW ZE
If AOCD AJAL then which of the following statements are true 1 OC JA II E IV OD AL ZCOD ZAJL ZDCO A B C JAL I only II only I and III
Geometry
Solution of triangles
If AOCD AJAL then which of the following statements are true 1 OC JA II E IV OD AL ZCOD ZAJL ZDCO A B C JAL I only II only I and III
Identify the center and radius of the circle x y 3 16 center x y radius
Geometry
Solution of triangles
Identify the center and radius of the circle x y 3 16 center x y radius
Select all true statements C A Show your work here CB BE AB BD 4 6 B 6 4 AB BE ZBACZBDE because vertical angles are congruent CB BD The triangles are congruent by the ASA criterion ZABC ZDBE because vertical angles are congruent The triangles are congruent by the SAS criterion D The triangles are congruent by the SSA criterion E
Geometry
Solution of triangles
Select all true statements C A Show your work here CB BE AB BD 4 6 B 6 4 AB BE ZBACZBDE because vertical angles are congruent CB BD The triangles are congruent by the ASA criterion ZABC ZDBE because vertical angles are congruent The triangles are congruent by the SAS criterion D The triangles are congruent by the SSA criterion E
Solve for x Leave your answer in simplest radical form 2
Geometry
Solution of triangles
Solve for x Leave your answer in simplest radical form 2