Chemical Bonding Questions and Answers

The volume of 0 0168 mol of O2 obtained by decomposition of KClO3 and collected by displacement of water is 428 mL at a pressure of 754 mm Hg at 25 C The pressure of water vapour at 25 C is OA 18 mm Hg OB 20 mm Hg C 22 mm Hg
Physical Chemistry
Chemical Bonding
The volume of 0 0168 mol of O2 obtained by decomposition of KClO3 and collected by displacement of water is 428 mL at a pressure of 754 mm Hg at 25 C The pressure of water vapour at 25 C is OA 18 mm Hg OB 20 mm Hg C 22 mm Hg
In the organic compound 5 CH CH CH C CH C CH the state of hybridization of carbons 2 4 and 6 are in the following sequence O sp sp sp O sp sp sp O sp sp sp O sp sp sp
Physical Chemistry
Chemical Bonding
In the organic compound 5 CH CH CH C CH C CH the state of hybridization of carbons 2 4 and 6 are in the following sequence O sp sp sp O sp sp sp O sp sp sp O sp sp sp
4 Which of the following pairings is incorrect in describing the spin states of d electrons in complexes Tetrahedral low spin Square planar low spin Octahedral Strong field ligand low spin Octahedral Weak field ligand high spin
Physical Chemistry
Chemical Bonding
4 Which of the following pairings is incorrect in describing the spin states of d electrons in complexes Tetrahedral low spin Square planar low spin Octahedral Strong field ligand low spin Octahedral Weak field ligand high spin
0 01 mol of CH4 and 0 96 g of oxygen were enclosed in a flask maintained at a temperature 300 K The pressure inside the flask was found to be 101325 Nm 2 Calculate the volume of the flask Also tell what is the partial pressure of each gas
Physical Chemistry
Chemical Bonding
0 01 mol of CH4 and 0 96 g of oxygen were enclosed in a flask maintained at a temperature 300 K The pressure inside the flask was found to be 101325 Nm 2 Calculate the volume of the flask Also tell what is the partial pressure of each gas
The correct increasing order of the oxidation state of sulphur in the anions 14 50 250 2 0 2 20 2 is SC a SO2 SO S 0 S 0 2 c S O2 SO3 S O SO 2 3 b SO 2 S 02 S 0 so d S 0 S 0 SO SO 2 C 1 74
Physical Chemistry
Chemical Bonding
The correct increasing order of the oxidation state of sulphur in the anions 14 50 250 2 0 2 20 2 is SC a SO2 SO S 0 S 0 2 c S O2 SO3 S O SO 2 3 b SO 2 S 02 S 0 so d S 0 S 0 SO SO 2 C 1 74
Q 35 36 Hybridisation is the measure to express the molecular shapes reson ably Hybridisation although theoretical but it is highly correlated with molecular shapes or inter orbital angles If there is any variation in geometry on the basis of VSEPR theory the apparent variation in hybridisation can be observed and the following characteristic relationship is the easiest way to interpret that variation Any hybrid orbital made by s and p orbitals is characterised by the following rela tionship 1 or fp and i i 1 for sp i 3 and sp i 2 for an orbital f fp 1 while all the sp hybrids of given atom must satisfy the condition Ef 1 00 d and the inter orbital angle between two equivalent same f and same fp hybrid orbitals is given by cos 8 fp 35 In BFCIBr molecule which of the following bond have minimum 1 character provided to the central atom A B Cl B B F C B Br D Cannot be predicted
Physical Chemistry
Chemical Bonding
Q 35 36 Hybridisation is the measure to express the molecular shapes reson ably Hybridisation although theoretical but it is highly correlated with molecular shapes or inter orbital angles If there is any variation in geometry on the basis of VSEPR theory the apparent variation in hybridisation can be observed and the following characteristic relationship is the easiest way to interpret that variation Any hybrid orbital made by s and p orbitals is characterised by the following rela tionship 1 or fp and i i 1 for sp i 3 and sp i 2 for an orbital f fp 1 while all the sp hybrids of given atom must satisfy the condition Ef 1 00 d and the inter orbital angle between two equivalent same f and same fp hybrid orbitals is given by cos 8 fp 35 In BFCIBr molecule which of the following bond have minimum 1 character provided to the central atom A B Cl B B F C B Br D Cannot be predicted
Chose the incorrect statement The constituents of a compound cannot be O separated into simpler substances by physical methods O The properties of a compound are same as its constituent elements An element is consisting of only one type of O particles and these particles may be atoms molecules Atoms of different elements are different in nature
Physical Chemistry
Chemical Bonding
Chose the incorrect statement The constituents of a compound cannot be O separated into simpler substances by physical methods O The properties of a compound are same as its constituent elements An element is consisting of only one type of O particles and these particles may be atoms molecules Atoms of different elements are different in nature
7 Which of the following statements are correct about CO3 I The hybridisation of central atom is sp II Its resonance structures have one C O single bond and two C O double bonds III The average formal charge on each oxygen atom is 0 67 units IV All C O bond lengths are equal a I and II only c III and IV only b I and III only d II and IV only
Physical Chemistry
Chemical Bonding
7 Which of the following statements are correct about CO3 I The hybridisation of central atom is sp II Its resonance structures have one C O single bond and two C O double bonds III The average formal charge on each oxygen atom is 0 67 units IV All C O bond lengths are equal a I and II only c III and IV only b I and III only d II and IV only
0 0 2 Parcul Statement 1 Curve 1 represents the less stable state of the system for H ion Statement 2 Curve 2 represents the most stable state of the system for H ion d Who postulated Valence shell electron pair repulsion theory Explain with examples why in sp hybrid compounds the bond length between Carbon Carbon atom is less than bond length between Carbon Carbon atoms in sp hybrid compounds 2 e Hybridization is an energy requiring process yet it occurs why Explain geometry of the following compounds 131 NH4 PC16 Cu NH3 4 POCI3 ICL BH Q 3 a Explain molecular orbital theory How is it superior to Valence bond theory in explaining the properties of compounds going through examples Workout bond order and magnetic properties of these molecules of Li and B 131 presence of lone pair affect the h Explain Gillespie and Nyholm theory with examples
Physical Chemistry
Chemical Bonding
0 0 2 Parcul Statement 1 Curve 1 represents the less stable state of the system for H ion Statement 2 Curve 2 represents the most stable state of the system for H ion d Who postulated Valence shell electron pair repulsion theory Explain with examples why in sp hybrid compounds the bond length between Carbon Carbon atom is less than bond length between Carbon Carbon atoms in sp hybrid compounds 2 e Hybridization is an energy requiring process yet it occurs why Explain geometry of the following compounds 131 NH4 PC16 Cu NH3 4 POCI3 ICL BH Q 3 a Explain molecular orbital theory How is it superior to Valence bond theory in explaining the properties of compounds going through examples Workout bond order and magnetic properties of these molecules of Li and B 131 presence of lone pair affect the h Explain Gillespie and Nyholm theory with examples
5 What is the minimum volume of water required dissolve 1 g of calcium sulphate at 298 K Given For calcium sulphate Ksp 9 1 x a 3 02 L b 2 00 L d 2 43 L x 10 6 c 2 56 L
Physical Chemistry
Chemical Bonding
5 What is the minimum volume of water required dissolve 1 g of calcium sulphate at 298 K Given For calcium sulphate Ksp 9 1 x a 3 02 L b 2 00 L d 2 43 L x 10 6 c 2 56 L
a 100 mL b 20 mL c 40 mL 8 The equivalent mass of MnSO4 is half its molecular mass when it is converted to a Mn 0 3 b MnO 2 CPMT 1994 2 d MnO c MnO 4 11 of air containing 21 oxygen by volume in standard LDMT 20041
Physical Chemistry
Chemical Bonding
a 100 mL b 20 mL c 40 mL 8 The equivalent mass of MnSO4 is half its molecular mass when it is converted to a Mn 0 3 b MnO 2 CPMT 1994 2 d MnO c MnO 4 11 of air containing 21 oxygen by volume in standard LDMT 20041
Only One Correct Answer A B C D Glucose on complete reduction with HI and red phosphorus finally gives n hexane It reacts with acetic anhydride and gives hexaacetate derivatives Glucose combines with hydroxyl amine to form a monoxime Mild oxidation of glucose with Br water gives gluconic acid
Physical Chemistry
Chemical Bonding
Only One Correct Answer A B C D Glucose on complete reduction with HI and red phosphorus finally gives n hexane It reacts with acetic anhydride and gives hexaacetate derivatives Glucose combines with hydroxyl amine to form a monoxime Mild oxidation of glucose with Br water gives gluconic acid
The elements A B C D E and F have at omic numbers 19 16 10 12 17 and 11 respectively Answer the following a I dentify the strongest non metal b Name the alkaline earth metal c Name the elements which have the s ame valency d Identify the elements that have the s ame number of valence electrons e State the formula of the compound f ormed between the elements B and F
Physical Chemistry
Chemical Bonding
The elements A B C D E and F have at omic numbers 19 16 10 12 17 and 11 respectively Answer the following a I dentify the strongest non metal b Name the alkaline earth metal c Name the elements which have the s ame valency d Identify the elements that have the s ame number of valence electrons e State the formula of the compound f ormed between the elements B and F
74 The oxidation states of transition metal atoms in K Cr O7 KMnO4 and K FeO respectively are x y and z The sum of a y and is
Physical Chemistry
Chemical Bonding
74 The oxidation states of transition metal atoms in K Cr O7 KMnO4 and K FeO respectively are x y and z The sum of a y and is
63 The shape structure of XeFs and XeO3F2 respectively are A octahedral and square pyramidal B trigonal bipyramidal and trigonal bipyramidal C trigonal bipyramidal and pentagonal D pentagonal planar and trigonal bipyramidal
Physical Chemistry
Chemical Bonding
63 The shape structure of XeFs and XeO3F2 respectively are A octahedral and square pyramidal B trigonal bipyramidal and trigonal bipyramidal C trigonal bipyramidal and pentagonal D pentagonal planar and trigonal bipyramidal
3 A colourless solid X on heating evolved CO and also gave a white residue soluble in water Residue also gave CO when treated with dilute acid X is a Li CO3 c Ca HCO3 2 b CaCO3 d NaHCO3
Physical Chemistry
Chemical Bonding
3 A colourless solid X on heating evolved CO and also gave a white residue soluble in water Residue also gave CO when treated with dilute acid X is a Li CO3 c Ca HCO3 2 b CaCO3 d NaHCO3
Note this is a multi select question Isostoichiometric species have the same molecular formula but different electronic configuration Select ALL the isostoichiometric species from the list below ON N N N O H2 H H 111 Q Q no 2
Physical Chemistry
Chemical Bonding
Note this is a multi select question Isostoichiometric species have the same molecular formula but different electronic configuration Select ALL the isostoichiometric species from the list below ON N N N O H2 H H 111 Q Q no 2
Consider the following interaction of atomic orbitals 8 0 8 Answer 00 01 b 8 8 Out of the above combination X Number of non bonding combinations Y Number of combinations that produce only antibonding molecular orbital Z Number of combinations that produce only bonding molecular orbital V Number of combinations that produce bonding T molecular orbital W Number of combinations that produce antibonding T molecular orbital The value of X Y Z V Wis 1 e 8 X 02 02 c 3 1 X X X 04 04 05 06 E CO 07 7
Physical Chemistry
Chemical Bonding
Consider the following interaction of atomic orbitals 8 0 8 Answer 00 01 b 8 8 Out of the above combination X Number of non bonding combinations Y Number of combinations that produce only antibonding molecular orbital Z Number of combinations that produce only bonding molecular orbital V Number of combinations that produce bonding T molecular orbital W Number of combinations that produce antibonding T molecular orbital The value of X Y Z V Wis 1 e 8 X 02 02 c 3 1 X X X 04 04 05 06 E CO 07 7
The first AH and second AH ionisation enthalpies in kJ mol and the electron gain enthalpy AH in kJ mol of the elements I II eg III IV and V are given below Elements A H AgH I 520 60 II 419 48 III 1681 328 IV 1008 295 V 2372 48 The most reactive and the least reactive element amongst these are respectively a I and V c II and V A H 7300 3051 3374 1846 5251 b V and II d IV and V
Physical Chemistry
Chemical Bonding
The first AH and second AH ionisation enthalpies in kJ mol and the electron gain enthalpy AH in kJ mol of the elements I II eg III IV and V are given below Elements A H AgH I 520 60 II 419 48 III 1681 328 IV 1008 295 V 2372 48 The most reactive and the least reactive element amongst these are respectively a I and V c II and V A H 7300 3051 3374 1846 5251 b V and II d IV and V
A sample of sulphuric acid is 49 by mass 100 ml of it on titration with 12 N NaOH required 50 ml of NaOH solution The density of sample of sulphuric acid is 1 1 2 g ml 2 0 8 g ml 3 0 6 g ml J
Physical Chemistry
Chemical Bonding
A sample of sulphuric acid is 49 by mass 100 ml of it on titration with 12 N NaOH required 50 ml of NaOH solution The density of sample of sulphuric acid is 1 1 2 g ml 2 0 8 g ml 3 0 6 g ml J
Consider the following interaction of atomic orbitals no f Hoof a b d J S 8 8 Out of the above combination J S e c 8 88 J S X Number of non bonding combinations Y Number of combinations that produce only antibonding molecular orbital Z Number of combinations that produce only bonding molecular orbital V Number of combinations that produce bonding molecular orbital W Number of combinations that produce antibonding molecular orbital The value of X V 7 Wis
Physical Chemistry
Chemical Bonding
Consider the following interaction of atomic orbitals no f Hoof a b d J S 8 8 Out of the above combination J S e c 8 88 J S X Number of non bonding combinations Y Number of combinations that produce only antibonding molecular orbital Z Number of combinations that produce only bonding molecular orbital V Number of combinations that produce bonding molecular orbital W Number of combinations that produce antibonding molecular orbital The value of X V 7 Wis
Answer ANY 10 question from Q39 to Q50 1x10 10 Read the passage given below and answer the following questions Ionization Energy In chemistry Ionization energy is also called as ionization potential Ionization energy is the energy required to remove an electron from a gaseous atom or ion It is denoted by Ei The first or initial ionization energy or Ei of an atom or molecule is the energy required to removeone mole of electrons from one mole of isolated gaseous atom or ion It is quantitatively expressed as X energy Where X is any atom or molecule capable of ionization X is that atom or molecule with an electron removed and e is the removed electron This is generally an endothermic process Generally the closer the outermost electron are to the nucleus of the atom the higher the atoms or elements ionization energy In these questions Q No 39 to 41 a statement of Assertion followed by a statement of reason is given 39 Assertion A Ionization potential ofBe is greater than that of B Reason R The first electron released from Be is from ns orbital while it is from np orbital in B a Assertion and reason both are correct statements and reason is correct explanation for Assertion b Assertion and reason both are correct statements and reason is not correct explanation for Assertion Assertion is correct statement but reason is wrong statement d Assertion is wrong statement but reason is correct statement
Physical Chemistry
Chemical Bonding
Answer ANY 10 question from Q39 to Q50 1x10 10 Read the passage given below and answer the following questions Ionization Energy In chemistry Ionization energy is also called as ionization potential Ionization energy is the energy required to remove an electron from a gaseous atom or ion It is denoted by Ei The first or initial ionization energy or Ei of an atom or molecule is the energy required to removeone mole of electrons from one mole of isolated gaseous atom or ion It is quantitatively expressed as X energy Where X is any atom or molecule capable of ionization X is that atom or molecule with an electron removed and e is the removed electron This is generally an endothermic process Generally the closer the outermost electron are to the nucleus of the atom the higher the atoms or elements ionization energy In these questions Q No 39 to 41 a statement of Assertion followed by a statement of reason is given 39 Assertion A Ionization potential ofBe is greater than that of B Reason R The first electron released from Be is from ns orbital while it is from np orbital in B a Assertion and reason both are correct statements and reason is correct explanation for Assertion b Assertion and reason both are correct statements and reason is not correct explanation for Assertion Assertion is correct statement but reason is wrong statement d Assertion is wrong statement but reason is correct statement
Volume the number of particles and temperature are all held constant Which statement s best describes the speed distribution curve for the blue heavy particles compared to the speed distribution curve for the red light particles More than one statement is correct The shape of the speed distibution curves are similar The speed distribution curve for the blue heavy particles is wider indicating that the blue particles exhibit a large range of speeds The speed distribution curve for the red lighter particles is wider indicating that the red particles exibit a larger range of speeds The most probable speed peak for the blue heavy particles is located farther to the left indicating that the blue particles are slower thar the red particles The most probable speed for the red light particles is located farther to the left indicating that the red particles are faster than the blue particles
Physical Chemistry
Chemical Bonding
Volume the number of particles and temperature are all held constant Which statement s best describes the speed distribution curve for the blue heavy particles compared to the speed distribution curve for the red light particles More than one statement is correct The shape of the speed distibution curves are similar The speed distribution curve for the blue heavy particles is wider indicating that the blue particles exhibit a large range of speeds The speed distribution curve for the red lighter particles is wider indicating that the red particles exibit a larger range of speeds The most probable speed peak for the blue heavy particles is located farther to the left indicating that the blue particles are slower thar the red particles The most probable speed for the red light particles is located farther to the left indicating that the red particles are faster than the blue particles
e 04 Calculate Bond Pairs BP s 1 mark Calculate Lone Pairs LP s 1 mark Draw Lewis Structure 1 mark VSEPR Notation 0 5 mark Predict of then molecular Shape 0 5 mark Polarity 0 5 mark Provide the reason and justify your answer for the polarity
Physical Chemistry
Chemical Bonding
e 04 Calculate Bond Pairs BP s 1 mark Calculate Lone Pairs LP s 1 mark Draw Lewis Structure 1 mark VSEPR Notation 0 5 mark Predict of then molecular Shape 0 5 mark Polarity 0 5 mark Provide the reason and justify your answer for the polarity
Element A with minimum atomic number in which last electron has n m 3 but divisible by 3 bra How many given statements are correct about A n Principal quantum number m magnetic quantum number 1 Sum of group number and period number in Modern Periodic Table is even number ii Element belongs to s block iii Element belongs to IIIA group number iv Element is a metal v Atomic number of element is divisible by 3 vi Another element B has an atomic number atomic number of A 10 then element B belongs to III B group vii Element A has largest radius in their period viii The group in which element A is present has maximum elements in Modern Periodic Table to pa
Physical Chemistry
Chemical Bonding
Element A with minimum atomic number in which last electron has n m 3 but divisible by 3 bra How many given statements are correct about A n Principal quantum number m magnetic quantum number 1 Sum of group number and period number in Modern Periodic Table is even number ii Element belongs to s block iii Element belongs to IIIA group number iv Element is a metal v Atomic number of element is divisible by 3 vi Another element B has an atomic number atomic number of A 10 then element B belongs to III B group vii Element A has largest radius in their period viii The group in which element A is present has maximum elements in Modern Periodic Table to pa
Xe Oa Calculate Bond Pairs BP s 1 mark Calculate Lone Pairs LP s 1 mark Draw Lewis Structure 1 mark VSEPR Notation 0 5 mark Predict of then molecular Shape 0 5 mark Polarity 0 5 mark Provide the reason and justify your answer for the polarity
Physical Chemistry
Chemical Bonding
Xe Oa Calculate Bond Pairs BP s 1 mark Calculate Lone Pairs LP s 1 mark Draw Lewis Structure 1 mark VSEPR Notation 0 5 mark Predict of then molecular Shape 0 5 mark Polarity 0 5 mark Provide the reason and justify your answer for the polarity
1 What are the electron counts for the two complexes 2 Sketch the SALCs for the orbitals on the two ethylene ligands in the left complex and assign their Mulliken symbols in D2h point group symmetry H C CH Ph Ph Ph Ph H C CH B C6F5 3 C H6 H C Ph Mo Ph B C6F5 3 Ph Ph
Physical Chemistry
Chemical Bonding
1 What are the electron counts for the two complexes 2 Sketch the SALCs for the orbitals on the two ethylene ligands in the left complex and assign their Mulliken symbols in D2h point group symmetry H C CH Ph Ph Ph Ph H C CH B C6F5 3 C H6 H C Ph Mo Ph B C6F5 3 Ph Ph
nich of the following combinations would form a solution 1 Water and ethanol II Sand and table salt III Oxygen and nitrogen IV Oil and vinegar A I B II C III D II and IV E I and III
Physical Chemistry
Chemical Bonding
nich of the following combinations would form a solution 1 Water and ethanol II Sand and table salt III Oxygen and nitrogen IV Oil and vinegar A I B II C III D II and IV E I and III
In which of the following arrangements the given sequence is not strictly according to the property indicated against it a HF HCl HBr HI increasing acidic strength b HO HS H Se H Te increasing pK values 2 2 2 2 a c NH3 PH3 AsH3 SbH3 increasing acidic character d CO SiO2 SnO PbO increasing oxidising
Physical Chemistry
Chemical Bonding
In which of the following arrangements the given sequence is not strictly according to the property indicated against it a HF HCl HBr HI increasing acidic strength b HO HS H Se H Te increasing pK values 2 2 2 2 a c NH3 PH3 AsH3 SbH3 increasing acidic character d CO SiO2 SnO PbO increasing oxidising
For the following reaction which can be inferred from the figur A B conc A A B 50 Time min d A d B dt at t 0 dt B At least one intermediate is formed C The rate of formation of B is maximum at t 0 D the reaction reaches equilibrium in 50 minutes
Physical Chemistry
Chemical Bonding
For the following reaction which can be inferred from the figur A B conc A A B 50 Time min d A d B dt at t 0 dt B At least one intermediate is formed C The rate of formation of B is maximum at t 0 D the reaction reaches equilibrium in 50 minutes
69 H2 g and N2 g were placed in a vessel of constant volume and allowed to reach equilibrium according to the following reaction 92 kJ N2 g 2NH3 AHxn 3H g Concentration N H NH Time t t Which of the following is are true for the system between t t I The temperature of the system will decrease II The rates of the forward and reverse reactions were equal III The rate of formation of NH3 is equal to the rate of disappearance of H IV If more NH3 g is added to the system at time to while the temperature is held constant total pressure in the container will decrease A I and II B II and IV C III only D II only
Physical Chemistry
Chemical Bonding
69 H2 g and N2 g were placed in a vessel of constant volume and allowed to reach equilibrium according to the following reaction 92 kJ N2 g 2NH3 AHxn 3H g Concentration N H NH Time t t Which of the following is are true for the system between t t I The temperature of the system will decrease II The rates of the forward and reverse reactions were equal III The rate of formation of NH3 is equal to the rate of disappearance of H IV If more NH3 g is added to the system at time to while the temperature is held constant total pressure in the container will decrease A I and II B II and IV C III only D II only
Read the passage given below and answer the following question The shape of a molecule depends upon the number of valence shell electron pai lp and bp around the central atom and magnitude of repulsive forces between them Sidgwick and Powell in 1940 proposed a theory which was later develope and redefined by Nyholm and Gillespie for predicting the shape of a molecule Th theory came to be known as VSEPR Valence Shell Electron Pair Repulsion theo According to it the valence shell is taken as a sphere with the electron pairs localizing on the spherical surface at maximum distance from one another The molecules are classified into the following two categories to predict the geometrical shapes of molecules using VSEPR theory Molecules in which the central atom has no lone pair Molecules in which the central atom has one or more lone pairs Which of the following statements is correct about PCI 5 molecule A All the bonds are equal B The geometry is octahedral C Five lone pairs are present on the central phosphorus atom It hee to
Physical Chemistry
Chemical Bonding
Read the passage given below and answer the following question The shape of a molecule depends upon the number of valence shell electron pai lp and bp around the central atom and magnitude of repulsive forces between them Sidgwick and Powell in 1940 proposed a theory which was later develope and redefined by Nyholm and Gillespie for predicting the shape of a molecule Th theory came to be known as VSEPR Valence Shell Electron Pair Repulsion theo According to it the valence shell is taken as a sphere with the electron pairs localizing on the spherical surface at maximum distance from one another The molecules are classified into the following two categories to predict the geometrical shapes of molecules using VSEPR theory Molecules in which the central atom has no lone pair Molecules in which the central atom has one or more lone pairs Which of the following statements is correct about PCI 5 molecule A All the bonds are equal B The geometry is octahedral C Five lone pairs are present on the central phosphorus atom It hee to
formed 4 none of the above is formed 63 CH CH CH HI A Bis 1 CH CH CH OH C6 Aq KOH B 2 CH CH CH 2 CH 0 3 CH CH CH 4 CH G CH OH 54 Consider the following statements about S2 reaction 3 4 63 CH CH CH HI A Ag KOH B Be Fon h 3 1 CH CH CH OH 2 CH CH CH 3 CH CH CH OH 64 S 2 34f4fsh41 H FR 4 CH G CH
Physical Chemistry
Chemical Bonding
formed 4 none of the above is formed 63 CH CH CH HI A Bis 1 CH CH CH OH C6 Aq KOH B 2 CH CH CH 2 CH 0 3 CH CH CH 4 CH G CH OH 54 Consider the following statements about S2 reaction 3 4 63 CH CH CH HI A Ag KOH B Be Fon h 3 1 CH CH CH OH 2 CH CH CH 3 CH CH CH OH 64 S 2 34f4fsh41 H FR 4 CH G CH
TC0152 6 The bond energies of F Cl Br and I are 155 4 243 6 193 2 and 151 2 kJ mol respectively The strongest bond is 1 F F 3 Br Br 2 2 CI CI 4 I I TC0153
Physical Chemistry
Chemical Bonding
TC0152 6 The bond energies of F Cl Br and I are 155 4 243 6 193 2 and 151 2 kJ mol respectively The strongest bond is 1 F F 3 Br Br 2 2 CI CI 4 I I TC0153
2 are heat TC0154 138 Heat evolved in the reaction H Cl 2HCl is 182 kJ Bond energies of H H and Cl Cl are 430 and 242 kJ mol respectively The H Cl bond energy is 1 245 kJ mol 3 336 kl mott 2 427 kJ mol 4 154 kl mort
Physical Chemistry
Chemical Bonding
2 are heat TC0154 138 Heat evolved in the reaction H Cl 2HCl is 182 kJ Bond energies of H H and Cl Cl are 430 and 242 kJ mol respectively The H Cl bond energy is 1 245 kJ mol 3 336 kl mott 2 427 kJ mol 4 154 kl mort
9 The enthalpy change for the reaction H g CH g CH g is The bond energies are in kCal mol H H 103 C H 99 C C 80 C C 145 1 10 kCal mol TC0155 2 10 kCal mol 3 30 kCal mol 4 30 C
Physical Chemistry
Chemical Bonding
9 The enthalpy change for the reaction H g CH g CH g is The bond energies are in kCal mol H H 103 C H 99 C C 80 C C 145 1 10 kCal mol TC0155 2 10 kCal mol 3 30 kCal mol 4 30 C
83 An endothermic reaction A Bhave an activation 90 energy 15 kCal mol and the heat of the reaction is 5 kcal mol The activation energy of the reaction B A is 1 20 kCal mol 3 10 kCal mol 2 15 kcal mol 4 Zero CK0091
Physical Chemistry
Chemical Bonding
83 An endothermic reaction A Bhave an activation 90 energy 15 kCal mol and the heat of the reaction is 5 kcal mol The activation energy of the reaction B A is 1 20 kCal mol 3 10 kCal mol 2 15 kcal mol 4 Zero CK0091
For a given reaction AH 30 kJ mol 1 and AS 40 JK 1 mol 1 The reaction is spontaneous at 300 K 550 K 800 K 650 K
Physical Chemistry
Chemical Bonding
For a given reaction AH 30 kJ mol 1 and AS 40 JK 1 mol 1 The reaction is spontaneous at 300 K 550 K 800 K 650 K
He and a gas X having the same volume diffuse through a porous partition is 15 and 30 seconds respectively The gas X can be H 02 CH4
Physical Chemistry
Chemical Bonding
He and a gas X having the same volume diffuse through a porous partition is 15 and 30 seconds respectively The gas X can be H 02 CH4
Two Liquids A and B were added to a container and the pressure exerted by the solution was fou nd to be greater than the individual vapour pressure of both A and B Then which of the given optio ns cannot be correct explanation of above case Options A and B may be perfectly immiscible A and B may form a minimum boiling azeotrope A and B may show positive deviation from Raoult s law must have greater mole fraction in vapour phase
Physical Chemistry
Chemical Bonding
Two Liquids A and B were added to a container and the pressure exerted by the solution was fou nd to be greater than the individual vapour pressure of both A and B Then which of the given optio ns cannot be correct explanation of above case Options A and B may be perfectly immiscible A and B may form a minimum boiling azeotrope A and B may show positive deviation from Raoult s law must have greater mole fraction in vapour phase
1 NH 3 SO 18 The densities of two gases are in the ratio of 1 16 The ratio of their rates of diffusion is 1 16 1 2 4 1 3 1 4 4 1 16 IG0018 25 At relatively H
Physical Chemistry
Chemical Bonding
1 NH 3 SO 18 The densities of two gases are in the ratio of 1 16 The ratio of their rates of diffusion is 1 16 1 2 4 1 3 1 4 4 1 16 IG0018 25 At relatively H
4 Decrease in the concentration of Ag ions EC0064 52 E for the reaction Fe Zn Zn Fe is 0 35 V The given cell reaction is 1 spontaneous 3 in equilibrium 2 non spontaneous 4 can t say anything EC0065 59 000X
Physical Chemistry
Chemical Bonding
4 Decrease in the concentration of Ag ions EC0064 52 E for the reaction Fe Zn Zn Fe is 0 35 V The given cell reaction is 1 spontaneous 3 in equilibrium 2 non spontaneous 4 can t say anything EC0065 59 000X
A compound is found to contain 38 65 carbon 16 25 hydrogen and 45 09 nitrogen by ma What is the empirical formula for this compound
Physical Chemistry
Chemical Bonding
A compound is found to contain 38 65 carbon 16 25 hydrogen and 45 09 nitrogen by ma What is the empirical formula for this compound
A 2 4 L fixed volume container have only N at 300 K and 7 atm pressure At 300 K N and H completely react a to form NH3 and N H4 The pressure of final mixture Final mixture contain only N H4 and NH is 3 atm at 300 K Reaction are assume R 0 08 atm L mol K Reaction 1 N g 3H g 2NH3 g Reaction II N g 2H g N H g Consider the following statements 1 Mass of NH3 and N H4 in final mixture are x and y g respectively Then x is more than y II Equal mass of N react used in Both reaction I and reaction II III Initial mixture of H and N contain 5 6 g N and 1 g H IV 0 6 g of H react according to reaction I V 50 mol of H react according to reaction II VI More mass of H and N react according to reaction I than reaction II The correct statement s is are 1 Only I II III V 2 Only II III IV V and VI
Physical Chemistry
Chemical Bonding
A 2 4 L fixed volume container have only N at 300 K and 7 atm pressure At 300 K N and H completely react a to form NH3 and N H4 The pressure of final mixture Final mixture contain only N H4 and NH is 3 atm at 300 K Reaction are assume R 0 08 atm L mol K Reaction 1 N g 3H g 2NH3 g Reaction II N g 2H g N H g Consider the following statements 1 Mass of NH3 and N H4 in final mixture are x and y g respectively Then x is more than y II Equal mass of N react used in Both reaction I and reaction II III Initial mixture of H and N contain 5 6 g N and 1 g H IV 0 6 g of H react according to reaction I V 50 mol of H react according to reaction II VI More mass of H and N react according to reaction I than reaction II The correct statement s is are 1 Only I II III V 2 Only II III IV V and VI
Conformation is the momentry arrangement of atoms in three dimension surrounding the sp hybridised carbon atom For C H6 mainly two conformers are possible viz eclipsed staggered Staggered is more stable conformer The standard free energy difference for two conformers is 2 76 K cal mol at 300K A G staggered C H6 7 k cal mol at 300 K A H natural C H6 27 9724 k cal mol at 300 K Take logex 2 3 logiox What of staggered C H6 is present in natural C H6 at 300 K A 1 B 99 C 10 D 90
Physical Chemistry
Chemical Bonding
Conformation is the momentry arrangement of atoms in three dimension surrounding the sp hybridised carbon atom For C H6 mainly two conformers are possible viz eclipsed staggered Staggered is more stable conformer The standard free energy difference for two conformers is 2 76 K cal mol at 300K A G staggered C H6 7 k cal mol at 300 K A H natural C H6 27 9724 k cal mol at 300 K Take logex 2 3 logiox What of staggered C H6 is present in natural C H6 at 300 K A 1 B 99 C 10 D 90
EC0042 The oxidation potential of Zn Cu Ag H and Ni electrodes are 0 76 V 0 34 V 0 80 V 0 V 0 55 V respectively Which of the following reaction will provide maximum voltage 1 Zn Cu Cu Zn 2Ag Zn 2H Cu 2 Zn 2Ag 3 H Cu 4 H NP 2H Ni HEMENG 28801
Physical Chemistry
Chemical Bonding
EC0042 The oxidation potential of Zn Cu Ag H and Ni electrodes are 0 76 V 0 34 V 0 80 V 0 V 0 55 V respectively Which of the following reaction will provide maximum voltage 1 Zn Cu Cu Zn 2Ag Zn 2H Cu 2 Zn 2Ag 3 H Cu 4 H NP 2H Ni HEMENG 28801
2 Chlorofluorocarbons such as CCI F M 137 5 and CCI F M 121 have been linked to ozone depletion in Antarctica As of 2004 these gases were found in 275 and 605 parts per trillion 10 by volume What are the concentrations of these gases under conditions typical of Antarctica stratosphere 200 K and 0 08 atm R 0 08 l atm K mol a CCI F 1 375 10 mol l CCl F 3 025 10 moll b CCI F 2 75 10 mol l CCI F 6 05 10 mol l CC1 F 2 75 10 mol 1 CC1 F 6 05 10 moll 10 d CCI F 1 375 10 mol 1 c
Physical Chemistry
Chemical Bonding
2 Chlorofluorocarbons such as CCI F M 137 5 and CCI F M 121 have been linked to ozone depletion in Antarctica As of 2004 these gases were found in 275 and 605 parts per trillion 10 by volume What are the concentrations of these gases under conditions typical of Antarctica stratosphere 200 K and 0 08 atm R 0 08 l atm K mol a CCI F 1 375 10 mol l CCl F 3 025 10 moll b CCI F 2 75 10 mol l CCI F 6 05 10 mol l CC1 F 2 75 10 mol 1 CC1 F 6 05 10 moll 10 d CCI F 1 375 10 mol 1 c
Choose the incorrect match 1 XeF6 2 Xe03 Molecule Hybridisation Shape 3 XeFq 4 XeOFq Only one correct answer A 1 B 2 C 3 sp sp sp f sp Octahedral Pyramidal Square planar Square pyramidal
Physical Chemistry
Chemical Bonding
Choose the incorrect match 1 XeF6 2 Xe03 Molecule Hybridisation Shape 3 XeFq 4 XeOFq Only one correct answer A 1 B 2 C 3 sp sp sp f sp Octahedral Pyramidal Square planar Square pyramidal
EET CHEMISTRY All India Major Test Series Phase l II Major Test 45 39 10 09 2020 11 Which of the following lanthanoid ions is Q 11 314 444 diamagnetic Ce 58 Sm 62 Yb 70 Eu 63 Atoms Ce 58 Sm 62 Yb 70 Eu 63 1 Yb 2 Ce 2 Ce 3 Sm 4 Eu 4 Eu 1 Yb 3 Sm
Physical Chemistry
Chemical Bonding
EET CHEMISTRY All India Major Test Series Phase l II Major Test 45 39 10 09 2020 11 Which of the following lanthanoid ions is Q 11 314 444 diamagnetic Ce 58 Sm 62 Yb 70 Eu 63 Atoms Ce 58 Sm 62 Yb 70 Eu 63 1 Yb 2 Ce 2 Ce 3 Sm 4 Eu 4 Eu 1 Yb 3 Sm
approach between Mendeleev s Periodic Law and Modern Periodic Law is classification of elements from atomic weight to atomic number 3 4 On the basis of quantum numbers justify that the sixth period of the periodic table should have 3 elements Ans In the modern periodic table each period starts with the filling of a new principal energy level Thus th
Physical Chemistry
Chemical Bonding
approach between Mendeleev s Periodic Law and Modern Periodic Law is classification of elements from atomic weight to atomic number 3 4 On the basis of quantum numbers justify that the sixth period of the periodic table should have 3 elements Ans In the modern periodic table each period starts with the filling of a new principal energy level Thus th