Gauss Law Questions and Answers

A mom conducting spherical shell of inner radius a and outer radius b has within its thickness a positive volume and r change density p M 7 where M is a constant the distance from the center Im addition a small of is located at that conten is change q a 9 Using Gaux s law find the electric field in the shell as is b b 5 find the potential difference between the immer nadius a and the outer radius bof the spherical shell c what value should I have if the electric field in the shell is to be uniform

A charged particle q 3 C lies in the center of a cube The length of one side of the cube is 144 cm A q 3 C Part a Calculate the electric flux that passes through the surface of the cube Enter answer here each part Please enter a numerical answer below Accepted formats are numbers or e based scientific notation e g 0 23 2 1e6 5 23e 8 No answer submitted Image size S M L Max Part b Calculate the total electric flux through only the 4 side walls of the cube not including the top or the bottom nswer below Accepted formats are numbers or e based scientific notation e a 0 23 2 1e6 5 23e 8 1 points Nm C 1 points Scroll to

An electric field is given by E 51 7y 8 3k crosses gaussian cube having side length 2m as shown in the figure Then the net charge inclosed in the cube in xEo then find x Z X

Electrostatics Quiz Set 1 2 1 How many electrons must be added to a neutral object to leave a net charge of 1 00Ca

field near the surface of this sheet and a cylindrical Gaussian surface The electric field has a large uniformly charged sheet field lines for the electric uniform strength of 200 N C and is perpendicular to the surface of the sheet The Gaussian surface is 0 02 m long and its circular ends have a diameter of 0 008 m a What is the total electric flux through the curved portion of the Gaussian surface b What is the total electric flux through each end of the Gaussian surface c How much charge is enclosed by the Gaussian surface d What is the charge density charge per unit area of the sheet 3 A 5 625 X10 A 562 5 b 281 25 1 30 x 10 15 a 4 9x10 10 200110 0 6 004 noteotsiihditor C O Kyr v 004 V 2 25 p e 5 625 x 10 5 62 4 885x10 12

The earth is struck by an average of 10 each second from lightning 2 How far apart are two protons if the

5 Using the given diagram show that the following is true PQ RQ SR TS PT RO SR TS RQ SR TS PT P S

In a cubical volume of side length a = 0.50 m, the electric field is Ē = E(1 + 2.5²) + Eo(1+2.2)ĵ, where E = 0.15 N/C. The cube has its sides parallel to the coordinate axes as shown in the figure. Determine the net charge within the cube in units of picocoulomb (1pC= 10-12 C). (Take co Answer: = 8.85 x 10-¹2 C2/(Nm²).)

(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN BELOW. A sphere of radius To carries a volume charge density på. A spherical cavity of radius To/2 is then scooped out and left empty, as shown. Points A and C are at the centers of the respective spheres. Give your answers in units of pro/co. A) What is the magnitude of the electric field at point A ? Answer: B) What is the magnitude of the electric field at point B? Answer: PE A C

An infinitely long metal cylinder of radius R and surface charge density σ is placed symmetrically with an imaginary surface of the shape of a prism. The length of prism is L and its 3 sides are all equal to 3R. The flux through the prism is : 1) πRLσ/3ɛ₀ 2) πRLσ/2ɛ₀ 3) πRLσ/ɛ₀ 4) 2πRLσ/ɛ₀

A neutral, aluminum pie plate is brought near to a positively charged foam board. When it is held near, what does the charge distribution on the aluminum pie plate look like? Tap on object to toggle through Charge Distribution options. In this situation, the aluminum pie plate is Tap to select or deselect answers Select all that apply. negatively-charged positively-charged electrically neutral polarized

An infinite thin sheet of charge, with uniform charge per unit area O, fills the xy plane. The total outward electric flux through an imaginary sphere of radius R, centered on the sheet, is (recall 4k = 1/€0): 4π R²σ/€0 2π R²σ/€0 0 π R²σ/€0 4π R²σ/(3€0)