# Gauss Law Questions and Answers

Physics

Gauss LawIn a cubical volume of side length a = 0.50 m, the electric field is
Ē = E(1 + 2.5²) + Eo(1+2.2)ĵ, where E = 0.15 N/C. The cube has
its sides parallel to the coordinate axes as shown in the figure. Determine the net
charge within the cube in units of picocoulomb
(1pC= 10-12 C).
(Take co
Answer:
=
8.85 x 10-¹2 C2/(Nm²).)

Physics

Gauss Law(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION
GIVEN BELOW.
A sphere of radius To carries a volume charge density på. A spherical cavity of
radius To/2 is then scooped out and left empty, as shown.
Points A and C are at the centers of the respective spheres.
Give your answers in units of pro/co.
A) What is the magnitude of the electric field at point A ?
Answer:
B) What is the magnitude of the electric field at point B?
Answer:
PE
A C

Physics

Gauss LawAn infinitely long metal cylinder of radius R and surface charge density σ is placed symmetrically with an imaginary surface of the shape of a prism. The length of prism is L and its 3 sides are all equal to 3R. The flux through the prism is :
1) πRLσ/3ɛ₀
2) πRLσ/2ɛ₀
3) πRLσ/ɛ₀
4) 2πRLσ/ɛ₀

Physics

Gauss LawA neutral, aluminum pie plate is brought near to a positively charged foam board. When it is held near, what does the charge distribution on the aluminum pie plate look like?
Tap on object to toggle through Charge Distribution options.
In this situation, the aluminum pie plate is
Tap to select or deselect answers Select all that apply.
negatively-charged
positively-charged
electrically neutral
polarized

Physics

Gauss LawAn infinite thin sheet of charge, with uniform charge per unit area O, fills the xy plane. The total outward electric flux through an imaginary sphere of radius R, centered on the sheet, is (recall 4k = 1/€0):
4π R²σ/€0
2π R²σ/€0
0
π R²σ/€0
4π R²σ/(3€0)

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