Biological Classification Questions and Answers

What is one common mistake taxonomists may make when attempting to place seemingly closely related species into a shared classification group The two species seem to be located in the same region on the planet The two species share many structural proteins genes and metabolic pathways The two species share similar morphology or character traits but their is not confirmed homology The two species share an evolutionary history based upon matching segments of DNA
Biology
Biological Classification
What is one common mistake taxonomists may make when attempting to place seemingly closely related species into a shared classification group The two species seem to be located in the same region on the planet The two species share many structural proteins genes and metabolic pathways The two species share similar morphology or character traits but their is not confirmed homology The two species share an evolutionary history based upon matching segments of DNA
Based on what you know and what you have learned abel the anatomy of the urchin with the letter that fits each organ You may also visit http purpleseaurchinreasource weebly com digestiverespiratory html a gills c Aristotle s Lantern b tubed feet d anus Data collection Visit http www ipacoa org Explorer axial organ gonad intestine stone Canal dy Section AA madreporite test madreporic amputa Click on the Filters on the left side of the page Click on Washington State and Alaska and you will see some platforms buoy disappear Then scroll down to Variables Select Dissolved Oxygen and you will see some platforms buoy disappear As you navigate each platform buoy a box will appear on the right Click on the Oxygen Percent Saturation Oxygen Pct Sat Spend time exploring the data at differ Depth is in parentheses Da P notice any pattes tooth perignathic girdle dorsal sec Jaboral haemal ring Co ambuecral termination polian mouth vesicle rotula GROSOPA perihaemal opulla Canal ASPAUS radial Water canal radial haemal strand
Biology
Biological Classification
Based on what you know and what you have learned abel the anatomy of the urchin with the letter that fits each organ You may also visit http purpleseaurchinreasource weebly com digestiverespiratory html a gills c Aristotle s Lantern b tubed feet d anus Data collection Visit http www ipacoa org Explorer axial organ gonad intestine stone Canal dy Section AA madreporite test madreporic amputa Click on the Filters on the left side of the page Click on Washington State and Alaska and you will see some platforms buoy disappear Then scroll down to Variables Select Dissolved Oxygen and you will see some platforms buoy disappear As you navigate each platform buoy a box will appear on the right Click on the Oxygen Percent Saturation Oxygen Pct Sat Spend time exploring the data at differ Depth is in parentheses Da P notice any pattes tooth perignathic girdle dorsal sec Jaboral haemal ring Co ambuecral termination polian mouth vesicle rotula GROSOPA perihaemal opulla Canal ASPAUS radial Water canal radial haemal strand
Endosymbiosis describes O One cell destroying another cell O One cell inside another cell providing a benefit O Two cells living close together to the benefit of both O One cell eating another
Biology
Biological Classification
Endosymbiosis describes O One cell destroying another cell O One cell inside another cell providing a benefit O Two cells living close together to the benefit of both O One cell eating another
Questions 8 11 refer to the following situation Ant zombification begins when an Ophiocordyceps fungus shoots spores onto an insect The fungus then takes over the ant s brain and causes it to move to a cool location The fungus then kills the ant when fruiting bodies erupt from the ant s head as in the picture and spread more spores Ants that are heterozygous at the brain power gene are resistant to zombification while both homozygous genotypes are susceptible The table below shows the numbers of ants that survive zombification for each genotype Genotype BB Bb bb ants at birth before zombification 250 400 350 ants after zombification 150 320 70 Q8 What is the absolute fitness of the BB genotype af
Biology
Biological Classification
Questions 8 11 refer to the following situation Ant zombification begins when an Ophiocordyceps fungus shoots spores onto an insect The fungus then takes over the ant s brain and causes it to move to a cool location The fungus then kills the ant when fruiting bodies erupt from the ant s head as in the picture and spread more spores Ants that are heterozygous at the brain power gene are resistant to zombification while both homozygous genotypes are susceptible The table below shows the numbers of ants that survive zombification for each genotype Genotype BB Bb bb ants at birth before zombification 250 400 350 ants after zombification 150 320 70 Q8 What is the absolute fitness of the BB genotype af
Which of the following methods initially identified the circular crater shape at depth in the earth s crust using waves from small explosions to image the subsurface O digging many trenches that exposed layers of sedimentary rock
Biology
Biological Classification
Which of the following methods initially identified the circular crater shape at depth in the earth s crust using waves from small explosions to image the subsurface O digging many trenches that exposed layers of sedimentary rock
This event also marks the boundary between the O Paleozoic and Mesozoic Mesozoic and Cenozoic Paleozoic and Cenozoic
Biology
Biological Classification
This event also marks the boundary between the O Paleozoic and Mesozoic Mesozoic and Cenozoic Paleozoic and Cenozoic
The extinction event at the above locality is best seen in the fossil record of which groups of organisms land plants fishes dinosaurs foraminifera mammals
Biology
Biological Classification
The extinction event at the above locality is best seen in the fossil record of which groups of organisms land plants fishes dinosaurs foraminifera mammals
Problem 1 10 P Figure 1 shows a phylogenetic tree of a small outbreak of bacterial pathogen Colors represent patients from which the samples were drawn Patient 1 Patient 4 Patient 2 Patient 5 Patient 3 Figure 1 Phylogenetic tree of the outbreak 1 1 5 P For each patient identify the MRCA of all their isolates Circle and label it on the tree 2 5 P Infer the transmission chain that most parsimoniously explains this phylogeny
Biology
Biological Classification
Problem 1 10 P Figure 1 shows a phylogenetic tree of a small outbreak of bacterial pathogen Colors represent patients from which the samples were drawn Patient 1 Patient 4 Patient 2 Patient 5 Patient 3 Figure 1 Phylogenetic tree of the outbreak 1 1 5 P For each patient identify the MRCA of all their isolates Circle and label it on the tree 2 5 P Infer the transmission chain that most parsimoniously explains this phylogeny
Seep Lip in I difference between eukaryotic and prokaryotic cells is that eukaryotic cells prokaryotic cells have DNA which is lacking in have membrane enclosed structures called organelles which are lacking in have a plasma membrane which is lacking in have a nucleoid region which is lacking in
Biology
Biological Classification
Seep Lip in I difference between eukaryotic and prokaryotic cells is that eukaryotic cells prokaryotic cells have DNA which is lacking in have membrane enclosed structures called organelles which are lacking in have a plasma membrane which is lacking in have a nucleoid region which is lacking in
13 Internal skull label bony elements only 15 Lateral skull label bony elements only
Biology
Biological Classification
13 Internal skull label bony elements only 15 Lateral skull label bony elements only
7 Mandible lateral view 8 Sphenoid superior view 10 Frontal anterior view 11 Parietal lateral view
Biology
Biological Classification
7 Mandible lateral view 8 Sphenoid superior view 10 Frontal anterior view 11 Parietal lateral view
14 Inferior skull label bony elements and only foramina canals 16 Anterior skull label bony elements only
Biology
Biological Classification
14 Inferior skull label bony elements and only foramina canals 16 Anterior skull label bony elements only
me next two questions ask you to think about how antibiotic resistance evolves within a atient infected by a tuberculosis bacterium that is sensitive to antibiotics It is a good dea to read both questions before you begin your answer a Describe the change that occurs in a population of tuberculosis bacteria with regard to antibiotic resistance within an infected patient during the generations BEFORE antibiotic treatment is initiated Make sure you explain both 1 WHAT changes and 2 HOW this change occurs b Describe the change that occurs in a population of tuberculosis bacteria with regard to antibiotic resistance within an infected patient AFTER antibiotic treatment is initiated Make sure you explain both 1 WHAT changes and 2 HOW this change occurs
Biology
Biological Classification
me next two questions ask you to think about how antibiotic resistance evolves within a atient infected by a tuberculosis bacterium that is sensitive to antibiotics It is a good dea to read both questions before you begin your answer a Describe the change that occurs in a population of tuberculosis bacteria with regard to antibiotic resistance within an infected patient during the generations BEFORE antibiotic treatment is initiated Make sure you explain both 1 WHAT changes and 2 HOW this change occurs b Describe the change that occurs in a population of tuberculosis bacteria with regard to antibiotic resistance within an infected patient AFTER antibiotic treatment is initiated Make sure you explain both 1 WHAT changes and 2 HOW this change occurs
What effect did the point mutation have on the sequenced polypeptide in this exercise Reference your results recorded in Data Table 2 in your explanation BI Type answer here Question 2 B IU What effect did the frameshift mutation have on the sequenced polypeptide in this exercise Reference your results recorded in Data Table 2 in your explanation T T O Word s
Biology
Biological Classification
What effect did the point mutation have on the sequenced polypeptide in this exercise Reference your results recorded in Data Table 2 in your explanation BI Type answer here Question 2 B IU What effect did the frameshift mutation have on the sequenced polypeptide in this exercise Reference your results recorded in Data Table 2 in your explanation T T O Word s
You are conducting an experiment by trying to reproduce the work performed in 1891 by Hans Driesch a German embryologist You are working with a fertilized sea urchin egg and allow it to complete the first cell division after fertilization You then carefully separate the two cells of the embryo and allow their development to continue Based on Driesch s experiment which result below would you expect to happen O Both of the cells will die O Both cells develop into complete and normal embryos that are somewhat smaller O One cell develops into a normal though smaller embryo the other dies O One cell develops into half an embryo the other develops into the other half of the embryo O One cell develops into a defective embryo and the other dies QUESTION 26 Why are viruses not considered to be organisms and not described as being alive O Virions are unable to reproduce by themselves O Virions are not able to metabolize by themselves O Virions are not able to synthesize DNA by themselves O Virions are not able to assemble spontaneously O Virions are unable to reproduce by themselves to metabolize by themselves or to assemble spontaneously
Biology
Biological Classification
You are conducting an experiment by trying to reproduce the work performed in 1891 by Hans Driesch a German embryologist You are working with a fertilized sea urchin egg and allow it to complete the first cell division after fertilization You then carefully separate the two cells of the embryo and allow their development to continue Based on Driesch s experiment which result below would you expect to happen O Both of the cells will die O Both cells develop into complete and normal embryos that are somewhat smaller O One cell develops into a normal though smaller embryo the other dies O One cell develops into half an embryo the other develops into the other half of the embryo O One cell develops into a defective embryo and the other dies QUESTION 26 Why are viruses not considered to be organisms and not described as being alive O Virions are unable to reproduce by themselves O Virions are not able to metabolize by themselves O Virions are not able to synthesize DNA by themselves O Virions are not able to assemble spontaneously O Virions are unable to reproduce by themselves to metabolize by themselves or to assemble spontaneously
mulight Microscopes were constructed by the end of the sixteenth century What is a compound microscope O It has a moveable stage O It has two lenses O Its lens is double the size of the original microscopes O The lens has two different colors O They have two different light sources QUESTION 31 Which of the following statements about viruses is not true O All viruses are obligatory intracellular parasites O All viruses are obligatory intercellular parasites O Viruses occur in a wide variety of very different shapes sizes and constructions O A viral host may be a plant an animal or a bacterial cell O Viral genetic material can be either RNA or DNA QUESTION 32 Potato spindle tuber disease which causes potatoes to become gnarled and cracked is caused by an infectious agent consisting of a small circular RNA molecule that totally lacks a protein coat These infectious agents are thought to exert their effects by interfering with the cell s normal path of gene expression Such an infectious agent is known as a n
Biology
Biological Classification
mulight Microscopes were constructed by the end of the sixteenth century What is a compound microscope O It has a moveable stage O It has two lenses O Its lens is double the size of the original microscopes O The lens has two different colors O They have two different light sources QUESTION 31 Which of the following statements about viruses is not true O All viruses are obligatory intracellular parasites O All viruses are obligatory intercellular parasites O Viruses occur in a wide variety of very different shapes sizes and constructions O A viral host may be a plant an animal or a bacterial cell O Viral genetic material can be either RNA or DNA QUESTION 32 Potato spindle tuber disease which causes potatoes to become gnarled and cracked is caused by an infectious agent consisting of a small circular RNA molecule that totally lacks a protein coat These infectious agents are thought to exert their effects by interfering with the cell s normal path of gene expression Such an infectious agent is known as a n
Who is generally credited with the discovery of cells O Leeuwenhoek Hooke Schleiden Schwann O Virchow QUESTION 40 The collection of bacteria that live on and within the human body are being isolated identified and characterized they are referred to as the human QUESTION 41
Biology
Biological Classification
Who is generally credited with the discovery of cells O Leeuwenhoek Hooke Schleiden Schwann O Virchow QUESTION 40 The collection of bacteria that live on and within the human body are being isolated identified and characterized they are referred to as the human QUESTION 41
What is the extinction coefficient in 1 M cm at 280 nm for the unfolded peptide with the following amino acid sequence MKWVYTFISLLW 12660 12615 12785 12490
Biology
Biological Classification
What is the extinction coefficient in 1 M cm at 280 nm for the unfolded peptide with the following amino acid sequence MKWVYTFISLLW 12660 12615 12785 12490
a With your total magnification set at 40x and the top thread in focus is the bottom thread visible In focus b With your total magnification set at 100x and the top thread in focus is the bottom thread visible In focus C With your total magnification set at 400x and the top thread in focus is the bottom thread visible In focus d What does this tell you about the relationship between magnification and depth of field
Biology
Biological Classification
a With your total magnification set at 40x and the top thread in focus is the bottom thread visible In focus b With your total magnification set at 100x and the top thread in focus is the bottom thread visible In focus C With your total magnification set at 400x and the top thread in focus is the bottom thread visible In focus d What does this tell you about the relationship between magnification and depth of field
Which statement is true regarding the pairing of bases in DNA O Cytosine is always bonded to thymine O Thymine is always bonded to adenine O Adenine is always bonded to cytosine Adenine is always bonded to guanine Which of the following is an example of a heterotroph O algae tiger moss flower
Biology
Biological Classification
Which statement is true regarding the pairing of bases in DNA O Cytosine is always bonded to thymine O Thymine is always bonded to adenine O Adenine is always bonded to cytosine Adenine is always bonded to guanine Which of the following is an example of a heterotroph O algae tiger moss flower
Which characteristic of the garden pea made it a good choice for Mendel s 1 point genetic experiments The garden pea has only one characteristic that varies OGarden peas only reproduce through the process of self pollination The pea plant has seven observable characteristics that are expressed in exactly two ways O The reproduction process for the garden pea occurs slowly Which statement is true regarding a dihybrid cross O A dihybrid cross has no relationship to a monohybrid cross A dihybrid cross involves two genes and up to four alleles A dihybrid cross involves two genes and exactly two alleles A dihybrid cross is exactly the same as a monohybrid cross 1 point
Biology
Biological Classification
Which characteristic of the garden pea made it a good choice for Mendel s 1 point genetic experiments The garden pea has only one characteristic that varies OGarden peas only reproduce through the process of self pollination The pea plant has seven observable characteristics that are expressed in exactly two ways O The reproduction process for the garden pea occurs slowly Which statement is true regarding a dihybrid cross O A dihybrid cross has no relationship to a monohybrid cross A dihybrid cross involves two genes and up to four alleles A dihybrid cross involves two genes and exactly two alleles A dihybrid cross is exactly the same as a monohybrid cross 1 point
Peer reviewed scientific journal CDC website WHO website Influencer blog Question 6 1 point Listen True or False Non enveloped viruses are lacking a lipid bilayer True
Biology
Biological Classification
Peer reviewed scientific journal CDC website WHO website Influencer blog Question 6 1 point Listen True or False Non enveloped viruses are lacking a lipid bilayer True
Place the viral infection steps in the correct order Entry Assembly Synthesis Release Attachment
Biology
Biological Classification
Place the viral infection steps in the correct order Entry Assembly Synthesis Release Attachment
When DNA sequences are used for phylogenetic analyses each nucleotide position can be considered a trait Using the data provided below 57 bases from the mitochondrial DNA sequences of three chameleons and one lizard map ONLY the synapomorphic traits onto the phylogenetic tree provided below Note the horizontal branch on the tree where each trait transition takes place by using a line and the number of the base base numbers can be determined using the 10 50 marks above the sequence As an example of how I want you to map the traits onto the tree I have chosen a trait that is NOT synapomorphic and mapped it onto the tree position 10 the trait in question is an A in the lizard and two species of Brookesia and transitions to G in Chamaeleo After mapping all of the synapomorphic traits count the total number of trait transitions required to support this tree and note this number next to your tree If you are not sure which traits are synapomorphic read the material in the tan box that starts on page 214 of the text and is entitled Phylogenies from DNA sequences NOTE the tree only shows the three chameleon species leaving out the lizard Uromastyx outgroup that is included in the DNA data so you can evaluate which base is ancestral for each position Uromastyx B theili B brygooi C feae 10 T 20 1 30 1 40 1 50 AAACCTTAAAAGACACCACAACCATATGAACAACAACACCAACAATCAGCACACTAC AAACACTACAAAATATAACAACTGCATGAACAACATCAACCACAGCAAACATTTTAC AAACACTACAAGACATAACAACAGCATGAACTACTTCAACAACAGCAAATATTACAC AAACCCTACGAGACGCAACAACAATATGATCCACTTCCOCACAACAAACACAATTT Brookesia theili
Biology
Biological Classification
When DNA sequences are used for phylogenetic analyses each nucleotide position can be considered a trait Using the data provided below 57 bases from the mitochondrial DNA sequences of three chameleons and one lizard map ONLY the synapomorphic traits onto the phylogenetic tree provided below Note the horizontal branch on the tree where each trait transition takes place by using a line and the number of the base base numbers can be determined using the 10 50 marks above the sequence As an example of how I want you to map the traits onto the tree I have chosen a trait that is NOT synapomorphic and mapped it onto the tree position 10 the trait in question is an A in the lizard and two species of Brookesia and transitions to G in Chamaeleo After mapping all of the synapomorphic traits count the total number of trait transitions required to support this tree and note this number next to your tree If you are not sure which traits are synapomorphic read the material in the tan box that starts on page 214 of the text and is entitled Phylogenies from DNA sequences NOTE the tree only shows the three chameleon species leaving out the lizard Uromastyx outgroup that is included in the DNA data so you can evaluate which base is ancestral for each position Uromastyx B theili B brygooi C feae 10 T 20 1 30 1 40 1 50 AAACCTTAAAAGACACCACAACCATATGAACAACAACACCAACAATCAGCACACTAC AAACACTACAAAATATAACAACTGCATGAACAACATCAACCACAGCAAACATTTTAC AAACACTACAAGACATAACAACAGCATGAACTACTTCAACAACAGCAAATATTACAC AAACCCTACGAGACGCAACAACAATATGATCCACTTCCOCACAACAAACACAATTT Brookesia theili
Use the given chapter titles below to organize what happens in the story in order Additionally provide a piece of information that helps to explain the title or what is learned from the narrator that will help you remember the major plot event from the chapter story Note This assignment is not simply about putting the titles in order Allie s Glove Packing Up and Leaving Pencey Ernie s Piano Bar Sunny Ackley and His Lousy Teeth The Edmont Hotel of Perverts Stradlater Gets Ready For His Date Life at the Museum
Biology
Biological Classification
Use the given chapter titles below to organize what happens in the story in order Additionally provide a piece of information that helps to explain the title or what is learned from the narrator that will help you remember the major plot event from the chapter story Note This assignment is not simply about putting the titles in order Allie s Glove Packing Up and Leaving Pencey Ernie s Piano Bar Sunny Ackley and His Lousy Teeth The Edmont Hotel of Perverts Stradlater Gets Ready For His Date Life at the Museum
cm 0 RESET MY NOTES 3 4 ALA Lab Data Time min 10 20 30 Time min 0 10 0 20 0 30 Diffusion Spot Diameter 1 Crystal mm 13 16 16 Rate of Diffusion for 1 Crystal mm hr Diffusion Spot Diameter 3 Crystals mm 19 23 27 Rate of Diffusion for 3 Crystals mm hr How to Measure Diffusion Spot Diameter 6 Crystals mm 20 29 X 37 Rate of Diffusion for 6 Crystals mm hr Rate mm h diameter mm time min x 60 min 5 6 7 Diffusion Rate Complete the following T TOUC One orystur m tweezers Place three crystals using tweezers Place six crystals int using tweezers A tim once all three dishes crystals Timer will pause at 10 the ruler to measure t spot diameter for eac Record in Lab Data Timer will pause at 20 Measure the diffusion diameter for each dish Record in Lab Data Timer will pause at 30 Measure the diffusion diameter for each dish Record in Lab Data Calculate diffusion rate time dish entry Recorc
Biology
Biological Classification
cm 0 RESET MY NOTES 3 4 ALA Lab Data Time min 10 20 30 Time min 0 10 0 20 0 30 Diffusion Spot Diameter 1 Crystal mm 13 16 16 Rate of Diffusion for 1 Crystal mm hr Diffusion Spot Diameter 3 Crystals mm 19 23 27 Rate of Diffusion for 3 Crystals mm hr How to Measure Diffusion Spot Diameter 6 Crystals mm 20 29 X 37 Rate of Diffusion for 6 Crystals mm hr Rate mm h diameter mm time min x 60 min 5 6 7 Diffusion Rate Complete the following T TOUC One orystur m tweezers Place three crystals using tweezers Place six crystals int using tweezers A tim once all three dishes crystals Timer will pause at 10 the ruler to measure t spot diameter for eac Record in Lab Data Timer will pause at 20 Measure the diffusion diameter for each dish Record in Lab Data Timer will pause at 30 Measure the diffusion diameter for each dish Record in Lab Data Calculate diffusion rate time dish entry Recorc
Per course policy on academic honesty reproduction or dissemination of this Use Table 2 to answer questions 5 through 8 You are a researcher evaluating the relationship of fingernail length to the microbial population underneath the nail after handwashing You have 12 volunteers 6 of which have short natural nails and 6 with longer artificial nails Both nail type groups are exposed to E coli JM109 and FCV The participants wash their hands using the same handwashing procedures and researchers determine the microbial population after handwashing The cumulative data is in the table below TABLE 2 Average counts of E coli JM109 log CFU per volunteer SD and FCV log TCID so per volunteer SD beneath fingernails before and after hand washing for all six hand washing procedures combined E coli JM109 Nail type Natural Artificial Before hand washing 6 17 0 59 A 6 57 0 47 B Before hand washing 3 06 0 47 A 3 69 0 52 B FCV After hand washing 4 11 0 47 A 4 81 0 85 B Average counts followed by different letters in the same column were significantly different P 0 05 Significant differences in E coli JM109 and FCV counts between the two nail types were determined by t test After hand washing 1 15 0 75 A 2 18 0 98 B Lin C M Wu F M Kim H K Doyle M P Michaels B S amp Williams L K 2003 A comparison of hand washing techniques to remove Escherichia coli and caliciviruses under natural or artificial fingernails Journal of Food Protection 66 5 Write a hypothesis that would have been supported because of this study 1 pt 8 Based on the table what can you conclude 1 pt 6 What are the independent and dependent variables What is the control group Why are control groups important 4 pts 7 What is one constant variable mentioned in the paragraph describing the study 1 pt
Biology
Biological Classification
Per course policy on academic honesty reproduction or dissemination of this Use Table 2 to answer questions 5 through 8 You are a researcher evaluating the relationship of fingernail length to the microbial population underneath the nail after handwashing You have 12 volunteers 6 of which have short natural nails and 6 with longer artificial nails Both nail type groups are exposed to E coli JM109 and FCV The participants wash their hands using the same handwashing procedures and researchers determine the microbial population after handwashing The cumulative data is in the table below TABLE 2 Average counts of E coli JM109 log CFU per volunteer SD and FCV log TCID so per volunteer SD beneath fingernails before and after hand washing for all six hand washing procedures combined E coli JM109 Nail type Natural Artificial Before hand washing 6 17 0 59 A 6 57 0 47 B Before hand washing 3 06 0 47 A 3 69 0 52 B FCV After hand washing 4 11 0 47 A 4 81 0 85 B Average counts followed by different letters in the same column were significantly different P 0 05 Significant differences in E coli JM109 and FCV counts between the two nail types were determined by t test After hand washing 1 15 0 75 A 2 18 0 98 B Lin C M Wu F M Kim H K Doyle M P Michaels B S amp Williams L K 2003 A comparison of hand washing techniques to remove Escherichia coli and caliciviruses under natural or artificial fingernails Journal of Food Protection 66 5 Write a hypothesis that would have been supported because of this study 1 pt 8 Based on the table what can you conclude 1 pt 6 What are the independent and dependent variables What is the control group Why are control groups important 4 pts 7 What is one constant variable mentioned in the paragraph describing the study 1 pt
Make the following solution 75mL 10X TBE 9M Tris Base 889M Boric acid 20mM EDTA You are Given Solid Tris 121 g mol and Boric Acid 61 8g mol You are given 5M EDTA
Biology
Biological Classification
Make the following solution 75mL 10X TBE 9M Tris Base 889M Boric acid 20mM EDTA You are Given Solid Tris 121 g mol and Boric Acid 61 8g mol You are given 5M EDTA
What is the significance of the Baltimore classification How might we be able to use this type of classification to learn more about viruses or ways to target them for treatments Rubrics
Biology
Biological Classification
What is the significance of the Baltimore classification How might we be able to use this type of classification to learn more about viruses or ways to target them for treatments Rubrics
Here is an example JIGSAW slide We do not have a Group 1 so this is the Group assignment for Article 1 Reduced Permeability Darby E M Trampari E Siasat P et al Molecular mechanisms of antibiotic resistance revisited Nat Rev Microbiol 21 280 295 2023 GRAM NEGATIVE GRAM POSITIVE Purpose The purpose of this section was to discuss the bacterial adaptations to prevent antibiotics from crossing the cell membrane This section discusses Gram positive and negative mechanisms for reducing membrane permeability Concept Antibiotics usage has reduced cell permeability bacteria have evolved ways to prevent antibiotics from entering the cell The antibiotics cannot pass the cellular membranes of both Gram positive and negative cells which is a pathogenic tactic for resisting antibiotics Examples In some Gram negative species Enterobacterales E coli K pneumoniae porin channels have been modified to prevent larger molecules antibiotics from entering the cell P aeruginosa and A baumannii produce only small porins making their outer membranes highly impermeable Some pathogenic Gram positive bacteria have changed the composition of the cytoplasmic membrane which reduces permeability of the antibiotics
Biology
Biological Classification
Here is an example JIGSAW slide We do not have a Group 1 so this is the Group assignment for Article 1 Reduced Permeability Darby E M Trampari E Siasat P et al Molecular mechanisms of antibiotic resistance revisited Nat Rev Microbiol 21 280 295 2023 GRAM NEGATIVE GRAM POSITIVE Purpose The purpose of this section was to discuss the bacterial adaptations to prevent antibiotics from crossing the cell membrane This section discusses Gram positive and negative mechanisms for reducing membrane permeability Concept Antibiotics usage has reduced cell permeability bacteria have evolved ways to prevent antibiotics from entering the cell The antibiotics cannot pass the cellular membranes of both Gram positive and negative cells which is a pathogenic tactic for resisting antibiotics Examples In some Gram negative species Enterobacterales E coli K pneumoniae porin channels have been modified to prevent larger molecules antibiotics from entering the cell P aeruginosa and A baumannii produce only small porins making their outer membranes highly impermeable Some pathogenic Gram positive bacteria have changed the composition of the cytoplasmic membrane which reduces permeability of the antibiotics
is the significance of the Baltimore classification How might we be able to use this type of classification to learn more about viruses or ways to target them for treatments
Biology
Biological Classification
is the significance of the Baltimore classification How might we be able to use this type of classification to learn more about viruses or ways to target them for treatments
Choose which of the following apply to complexity and body size by using the figure below Present 100 200 Origin of earth 300 400 600 Million 800 years ago 17 Billion years ago 3 4 First eukaryote to cre Bacteria 1 10 100 um um um Cyanobacteria Living Amphibian Fish Eurypterid p Dinosaur Trilobite 1 10 100 mm mm mm Length Whale 1 10 100 m m m Many of these larger animals have different internal transport systems in order to survive in comparison to smaller animals Most complex grades of animal organization can promote evolution of large body size A large animal has more surface area relative to its volume than a small animal of the same shape
Biology
Biological Classification
Choose which of the following apply to complexity and body size by using the figure below Present 100 200 Origin of earth 300 400 600 Million 800 years ago 17 Billion years ago 3 4 First eukaryote to cre Bacteria 1 10 100 um um um Cyanobacteria Living Amphibian Fish Eurypterid p Dinosaur Trilobite 1 10 100 mm mm mm Length Whale 1 10 100 m m m Many of these larger animals have different internal transport systems in order to survive in comparison to smaller animals Most complex grades of animal organization can promote evolution of large body size A large animal has more surface area relative to its volume than a small animal of the same shape
It s amazing how much money you can save by buying ground beef in bulk James observed He and Albert were driving home after their Saturday morning shopping trip True said Albert but I m not sure we have enough space in the freezer to store it all That s not necessary said James We don t have to freeze it We can just keep it in the fridge As long as we set the temperature control low enough the meat will be fine No it won t replied Albert we must divide it up into smaller servings and freeze everything we don t use today Never mind said James I ll take care of it Once they got home James spent some time reorganizing the freezer so that the 5 pound package of ground beef fit Over the next few weeks they would thaw it out in the refrigerator overnight take what they needed for the day and then put the rest back in the freezer One evening both James and Albert developed stomach cramps and diarrhea You see moaned Albert I told you that we should have divided the beef up so that each portion was only thawed out once Nonsense said James doubled over with cramps it couldn t have been the beef Freezing kills all the microbes that cause disease I learned in class that most microbes that cause disease in people are mesophiles and they grow best at body temperature This must be something else 1 Can microbes survive freezing 2 Does thawing meat in the fridge provide enough protection from potential pathogens 3 What would have been a better approach to prevent the roommates discomfort
Biology
Biological Classification
It s amazing how much money you can save by buying ground beef in bulk James observed He and Albert were driving home after their Saturday morning shopping trip True said Albert but I m not sure we have enough space in the freezer to store it all That s not necessary said James We don t have to freeze it We can just keep it in the fridge As long as we set the temperature control low enough the meat will be fine No it won t replied Albert we must divide it up into smaller servings and freeze everything we don t use today Never mind said James I ll take care of it Once they got home James spent some time reorganizing the freezer so that the 5 pound package of ground beef fit Over the next few weeks they would thaw it out in the refrigerator overnight take what they needed for the day and then put the rest back in the freezer One evening both James and Albert developed stomach cramps and diarrhea You see moaned Albert I told you that we should have divided the beef up so that each portion was only thawed out once Nonsense said James doubled over with cramps it couldn t have been the beef Freezing kills all the microbes that cause disease I learned in class that most microbes that cause disease in people are mesophiles and they grow best at body temperature This must be something else 1 Can microbes survive freezing 2 Does thawing meat in the fridge provide enough protection from potential pathogens 3 What would have been a better approach to prevent the roommates discomfort
2 3 4 5 6 Background Research Divide Paper by Topics Outlining Note taking Annotated bibliographies Starting point zing information for Academic Writing A In this tutorial you will learn how to synthesize information for academic writing in a variety of different disciplines that you may come across within your coursework at CSUB Click here to view tutorial in new tab best for mobile users Access Login Access is restricted to CSUB students currently enrolled faculty and staff Enter your NetID Password then click the Login button myCSUB NetID Password Login Clear Lookun NetID Reset Change Password DO NOT INCLUDE csub edu
Biology
Biological Classification
2 3 4 5 6 Background Research Divide Paper by Topics Outlining Note taking Annotated bibliographies Starting point zing information for Academic Writing A In this tutorial you will learn how to synthesize information for academic writing in a variety of different disciplines that you may come across within your coursework at CSUB Click here to view tutorial in new tab best for mobile users Access Login Access is restricted to CSUB students currently enrolled faculty and staff Enter your NetID Password then click the Login button myCSUB NetID Password Login Clear Lookun NetID Reset Change Password DO NOT INCLUDE csub edu
Viruses of Repute Describe viral structure How is Senetic information encoded What are the potential hosts of a virus How would we culture viruses Figure 1 A general viral particle 3 Examine the diagram below depicting viral infection of a typical cell a Describe what is happening in each of the five steps b What are the roles of the two cellular factors shown on the diagram Figure 2 A general viral life cycle Attachment w m Entry w 3333 ww Nucleus w m ww wm Synthesis Assembly Release
Biology
Biological Classification
Viruses of Repute Describe viral structure How is Senetic information encoded What are the potential hosts of a virus How would we culture viruses Figure 1 A general viral particle 3 Examine the diagram below depicting viral infection of a typical cell a Describe what is happening in each of the five steps b What are the roles of the two cellular factors shown on the diagram Figure 2 A general viral life cycle Attachment w m Entry w 3333 ww Nucleus w m ww wm Synthesis Assembly Release
Adaptation Yolk Sac Utilization in Fish Larvae a How it works Fish larvae heavily rely on the yolk sac for nourishment during the early stages of development The yolk sac is a specialized structure containing nutrient rich resources transferred from the egg As the larvae grow they gradually absorb and utilize these nutrients from the yolk sac b Benefit to the organism This adaptation provides a crucial energy source for fish larvae supporting their growth and development in the initial stages of life The yolk sac allows them to sustain themselves before transitioning to external food sources enhancing their survival chances c Peer reviewed citation Jones G P McCormick M I Srinivasan M Eagle J V 2004 Coral decline threatens fish biodiversity in marine reserves Proceedings of the National Academy of Sciences of the United States of America 101 21 8251 8253
Biology
Biological Classification
Adaptation Yolk Sac Utilization in Fish Larvae a How it works Fish larvae heavily rely on the yolk sac for nourishment during the early stages of development The yolk sac is a specialized structure containing nutrient rich resources transferred from the egg As the larvae grow they gradually absorb and utilize these nutrients from the yolk sac b Benefit to the organism This adaptation provides a crucial energy source for fish larvae supporting their growth and development in the initial stages of life The yolk sac allows them to sustain themselves before transitioning to external food sources enhancing their survival chances c Peer reviewed citation Jones G P McCormick M I Srinivasan M Eagle J V 2004 Coral decline threatens fish biodiversity in marine reserves Proceedings of the National Academy of Sciences of the United States of America 101 21 8251 8253
Part II If your goal is to characterize the ETPUM whose results are more informative yours or your boss s Why What do your results indicate about the nature of this microbe Does its biochemical composition most closely resemble that of a Gram positive or Gram negative organism Cheker DNA DIGA RNA R Nu O Gram positive Gram negative
Biology
Biological Classification
Part II If your goal is to characterize the ETPUM whose results are more informative yours or your boss s Why What do your results indicate about the nature of this microbe Does its biochemical composition most closely resemble that of a Gram positive or Gram negative organism Cheker DNA DIGA RNA R Nu O Gram positive Gram negative
This is a map of Permian age geography Discuss the contrast with how a modern map would look Bring in concepts of rifting and vicariance to explain these contrasts South America Cynognathus Africa India 2 Antarctica Lystrosaurus W Glossopteris Australia
Biology
Biological Classification
This is a map of Permian age geography Discuss the contrast with how a modern map would look Bring in concepts of rifting and vicariance to explain these contrasts South America Cynognathus Africa India 2 Antarctica Lystrosaurus W Glossopteris Australia
Jan 15 Jan 21 Must post first How would the use of bacteriocidal bacteriostatic or bacteriolytic antimicrob agents differ in their resulting cell counts total and viable How would the ef differ regarding the growth curve of the cells Use examples to support your
Biology
Biological Classification
Jan 15 Jan 21 Must post first How would the use of bacteriocidal bacteriostatic or bacteriolytic antimicrob agents differ in their resulting cell counts total and viable How would the ef differ regarding the growth curve of the cells Use examples to support your
How do prokaryotic cells exhibit cellular differentiation Describe one manner of differentiation and the purpose of such differentiation You must start a thread before you can read and reply to other threads
Biology
Biological Classification
How do prokaryotic cells exhibit cellular differentiation Describe one manner of differentiation and the purpose of such differentiation You must start a thread before you can read and reply to other threads
SAFAT RENK Using the figures Figur 3 28 book respectively as a starting point create a flowchart that indicates the basic steps of cell division and replisome movement in a dividing cell for both a rod shaped and a spherical cell Highlight differences in the process that are dependent upon cell morphology Include the bolded key terms from Section 3 4 of the book NEAR BR MILITACRILATES Origin of replication DNA origin replicates and gras DNA replication continues bideectionally DNA starts next round Septum forms 2 ring Division into two cel Terminator sequence Origin of replication Two plomes Fiz uma Zring Torminator aquanon Fact in cytoplasm Zring Old pole New pole New pole is now old 18 Copyright 2020 W W Norton Company lec Copyright 2020 W W Norton Company Inc After creating your flowchart answer the following New poles New polos are now nid Old pole Cell growth Beginning of cell division Old pole
Biology
Biological Classification
SAFAT RENK Using the figures Figur 3 28 book respectively as a starting point create a flowchart that indicates the basic steps of cell division and replisome movement in a dividing cell for both a rod shaped and a spherical cell Highlight differences in the process that are dependent upon cell morphology Include the bolded key terms from Section 3 4 of the book NEAR BR MILITACRILATES Origin of replication DNA origin replicates and gras DNA replication continues bideectionally DNA starts next round Septum forms 2 ring Division into two cel Terminator sequence Origin of replication Two plomes Fiz uma Zring Torminator aquanon Fact in cytoplasm Zring Old pole New pole New pole is now old 18 Copyright 2020 W W Norton Company lec Copyright 2020 W W Norton Company Inc After creating your flowchart answer the following New poles New polos are now nid Old pole Cell growth Beginning of cell division Old pole
Eukaryotic cell walls contain peptidoglycan O True False
Biology
Biological Classification
Eukaryotic cell walls contain peptidoglycan O True False
Which of the following types of cell walls is are made up of many layers of peptidoglycan none of the choices are correct O acid fast O Gram negative O Gram positive
Biology
Biological Classification
Which of the following types of cell walls is are made up of many layers of peptidoglycan none of the choices are correct O acid fast O Gram negative O Gram positive
day I want to talk about Mating Position in Bombay Night Frogs An Unconventional Approach 1 Our exploration today delves into the Bombay Night Frog Nyctibatrachus humayuni and its unique mating position known as dorsal straddling Unlike typical frog amplexus where the male clasps the female from behind Bombay Night Frogs engage in a peculiar dorsal straddling position with the male perching atop the female II This adaptation is particularly intriguing because it allows for a more efficient transfer of sperm The dorsal straddling position ensures that the male s sperm is directly deposited on the female s cloacal opening enhancing the chances of successful fertilization This unconventional mating adaptation in Bombay Night Frogs adds a captivating layer to our discussions on amphibian reproduction and showcases the diverse strategies employed by different species
Biology
Biological Classification
day I want to talk about Mating Position in Bombay Night Frogs An Unconventional Approach 1 Our exploration today delves into the Bombay Night Frog Nyctibatrachus humayuni and its unique mating position known as dorsal straddling Unlike typical frog amplexus where the male clasps the female from behind Bombay Night Frogs engage in a peculiar dorsal straddling position with the male perching atop the female II This adaptation is particularly intriguing because it allows for a more efficient transfer of sperm The dorsal straddling position ensures that the male s sperm is directly deposited on the female s cloacal opening enhancing the chances of successful fertilization This unconventional mating adaptation in Bombay Night Frogs adds a captivating layer to our discussions on amphibian reproduction and showcases the diverse strategies employed by different species
In the tree below Taxon C forms a sister group with Taxa D E and F A B C D E F G H True False 5 3
Biology
Biological Classification
In the tree below Taxon C forms a sister group with Taxa D E and F A B C D E F G H True False 5 3
In the tree below which groups form a monophyletic group clade A B C D E F G H D G and H C E and F C D E F and G A B C and D 1 5 3
Biology
Biological Classification
In the tree below which groups form a monophyletic group clade A B C D E F G H D G and H C E and F C D E F and G A B C and D 1 5 3
5 Analysis of organelle genetic material shows a high similarity to the genetic material of Bacteria group What does indicate phylogenetically
Biology
Biological Classification
5 Analysis of organelle genetic material shows a high similarity to the genetic material of Bacteria group What does indicate phylogenetically
3 Draw the structure of a basic Bacteria or Archaea cell and label the parts
Biology
Biological Classification
3 Draw the structure of a basic Bacteria or Archaea cell and label the parts
Your research or guiding question should do what Select ALL that apply Should be of interest to you Should be a topic that can be analyzed lead to new insights Should be researched in scholarly peer reviewed journals
Biology
Biological Classification
Your research or guiding question should do what Select ALL that apply Should be of interest to you Should be a topic that can be analyzed lead to new insights Should be researched in scholarly peer reviewed journals
H Thymine enol form O Adenine O Cytosine O Uracil 0 H Which base will thymine enol pair with in DNA Guanine O Thymine NH a Cytosine b Uracil d Guanine H C H c Thymine NH e Adenine
Biology
Biological Classification
H Thymine enol form O Adenine O Cytosine O Uracil 0 H Which base will thymine enol pair with in DNA Guanine O Thymine NH a Cytosine b Uracil d Guanine H C H c Thymine NH e Adenine